Answer:
found in the nucleus, has mass of one amu
Explanation:
The answer is 3 m. This is the area under the graph from t=2 to t=3, using the trapezium rule. 1/2 (2+4) * 1
I think its inside the loop i had this lesson last week :)
Here are the missing questions:
(a) How fast is the skier moving when she gets to the bottom of the hill?
(b) How much internal energy was generated in crossing the rough patch?
Part A
The initial kinetic energy of the skier is:

Part of this energy is then used to do work against the force of friction. Force of friction on the horizontal surface can be calculated using following formula:

The work is simply the force times the length:

So when the skier passes over the rough patch its energy is:

When the skier is going down the skill gravitational potential energy is transformed into the kinetic energy:

So the final energy of the skier is:

This energy is the kinetic energy of the skier:
Part B
We know that skier lost some of its kinetic energy when crossing over the rough patch. This energy is equal to the work done by the skier against the force of friction.