This is an Arithmetic Progression with 1st term 11 and common difference d=6
Number of Rows Number of seats Common difference " d"
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1st a₁ = 11
2nd a₁+d =17 d =2nd - 1st = 6
3rd a₁ +2d = 23 d =3rd - 2nd = 6
4th a₁ +3d = 29 d= 4th - 3rd = 6
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nth ROW a(n) = a₁ + (n-1)d
18th ROW a₁₈ = 11 + (18-1).6 = 11+(17)(6) = 113
General equation to predict the number of seat an the nth row:
Number of seats in nth row = a₁ + (n-1).d
I hope that works? i also tried to solved it and i got the same thing i just checked it and it said i got it right.
Answer:
12 m/s²
Step-by-step explanation:
mass of the car = 50 kg
The net force applied to the car is 800 - 200 = 600 N
Form the Newton's second law:
F = m*a
where F is the net force applied to the object, m is the mass of the object, and a is the acceleration of the object.
Then, the acceleration of the car (in m/s²) is:
a = F/m
a = 600/50
a = 12 m/s²
Answer:
hiiio......
Step-by-step explanation:
b)8 boxes...
