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2 years ago

There is a current of 0.99 a through a light bulb when its connected to a 9.7 v battery what is the resistance of the light bulb

Physics

1 answer:

denis23 [38]2 years ago

4 0

Ohm's law states that V=IR, where V=voltage, I=current(amps), and R=resistance (in Ohms).

Plugging the values into the above equation yields a resistance in the light bulb of 9.8 ohms

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According to Galileo, this quantity is not needed to keep a body in motion under ideal conditions.

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When Earth and the Moon are separated by a

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sergey [27]

1) Initial upward acceleration: $6.0 m/s^2$

2) Mass of burned fuel: $0.10\cdot 10^4 kg$

Explanation:

There are two forces acting on the rocket at the beginning:

- The force of gravity, of magnitude $F_g = mg$ , in the downward direction, where

$m=1.9\cdot 10^4 kg$ is the rocket's mass

$g=9.8 m/s^2$ is the acceleration of gravity

- The thrust of the motor, T, in the upward direction, of magnitude

$T=3.0\cdot 10^5 N$

According to Newton's second law of motion, the net force on the rocket must be equal to the product between its mass and its acceleration, so we can write:

$T-mg=ma$ (1)