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denpristay [2]
3 years ago
9

Two boxes sit side by side on a smooth horizontal surface. The lighter box 5.2 kg, the heavier box has a mass of 7.4kg (a) find

the contact force between these boxes when a horizontal force of 5.0 N is applied to the light box. (Hint: you need to calculate acceleration first)
Physics
1 answer:
Paladinen [302]3 years ago
8 0

OK.  So you're pushing on the small box, and on the other side of it, the small
box is pushing on the big box. So you're actually pushing both of them.

-- The total mass that you're pushing is (5.2 + 7.4) = 12.6 kg.

-- You're pushing it with 5.0N of force.

-- Acceleration of the whole thing = (force)/(mass) = 5/12.6 = <em>0.397 m/s²</em> (rounded)

-- Both boxes accelerate at the same rate. So the box farther away from you ...
the big one, with 7.4 kg of mass, accelerates at the same rate.

The force on it to make it accelerate is (mass) x (acceleration) =

                                                              (7.4 kg) x (5/12.6 m/s²) =  <em>2.936 N.</em>

The only force on the big box comes from the small box, pushing it from behind. 
So that same  <em>2.936N</em>  must be the contact force between the boxes.

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Anuta_ua [19.1K]
This is a good time to review Newton's 3rd law of motion:
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Gravitational force always acts in pairs.
Whatever force the Earth attracts something with,
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If Earth attracts a person with a gravitational force of <span><span>7.0 × 10² </span>newtons,
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</span>
5 0
3 years ago
Which of the following would increase​
bazaltina [42]

Answer:

1 and 3

Explanation:

<u>1 and 3  </u>

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7 0
2 years ago
Read 2 more answers
Two identical 0.400 kg masses are pressed against opposite ends of a light spring of force constant 1.75 N/cm, compressing the s
nlexa [21]

Answer:

0.853 m/s

Explanation:

Total energy stored in the spring = Total kinetic energy of the masses.

1/2ke² = 1/2m'v².................... Equation 1

Where k = spring constant of the spring, e = extension, m' = total mass, v = speed of the masses.

make v the subject of the equation,

v = e[√(k/m')].................... Equation 2

Given: e = 39 cm = 0.39 m, m' = 0.4+0.4 = 0.8 kg, k = 1.75 N/cm = 175 N/m.

Substitute into equation 2

v = 0.39[√(1.75/0.8)

v = 0.39[2.1875]

v = 0.853 m/s

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7 0
3 years ago
1.) Waves transfer ______ without moving ______
kondor19780726 [428]
I believe it goes as the following::

1) Waves transfer energy without moving particles

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6 0
3 years ago
A girl is shown at position A on a swing when the seat is directly below the support bar. The seat is then at height A as shown
MrRa [10]

Answer:

<u></u>

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The gravitational <em>potential energy </em>is directly proportional to the height of the objects with respect to some reference altitude. Thus, when the seat is at the position A the swing has the smallest potential energy and when the seat is at the <em>position B the swing has the greatest potential energy.</em>

Regarding the forms of energy, as the swing moves from point B to point A, it is going downward, gaining kinetic energy (speed) at the expense of the potential energy (losing altitude). When the seat passes by the position A, the kinetic energy is maximum and the potential energy is miminum. Then the seat starts to gain altitude again, losing the kinetic energy and gaining potential energy, up to it gets to the other end,

7 0
3 years ago
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