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Y_Kistochka [10]
3 years ago
13

Superman strikes a golf ball on the ground at a 38 degree angle above the horizontal at 147 m/s. What is the maximum height the

golf ball reaches?
255 m


418 m


687 m


1103 m
Physics
1 answer:
tino4ka555 [31]3 years ago
5 0

The ball is hit with an initial vertical velocity of

(147 m/s) sin(38º) ≈ 90.5 m/s

Recall that

<em>v </em>² - <em>u </em>² = 2 <em>a</em> ∆<em>y</em>

where <em>u</em> and <em>v</em> are initial and final velocities, respectively; <em>a</em> is acceleration; and ∆<em>y</em> is displacement.

Vertically, the ball is in freefall, so it is only subject to acceleration due to gravity, with magnitude <em>g</em> = 9.80 m/s² in the downward direction. At its maximum height, the ball has zero vertical velocity (<em>v</em> = 0) and the displacement is equal to the maximum height, so

0² - (90.5 m/s)² = 2 (-<em>g</em>) ∆<em>y</em>

∆<em>y</em> = (90.5 m/s)² / (2<em>g</em>)

∆<em>y</em> ≈ 418 m

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Answer:

Option (b)

Explanation:

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In case of fresh water:

Weight of the boat = weight of fresh water displaced by the boat

W = Volume of fresh water displaced x density of fresh water x g

W = V x 1 x g

W = V x g ....... (1)

In case of salt water:

Let the volume of salt water displaced is V'.

Weight of the boat = weight of salt water displaced by the boat

W = Volume of salt water displaced x density of salt water x g

W = V' x 1.02 x g    ..... (2)

Equate equation (1) and equation (2), we get

V x g = V' x 1.02 x g

V' = 0.98 V

Thus, option (b) is true.

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Answer: initially the packet was ascending up with the balloon.

Taking upward as positive direction;

initial velocity, u = 4.9 m/s

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a = -9.8 m/s²

time taken = t seconds

s = ut + 0.5at²

⇒ (h₂-h₁) = ut + 0.5at²

⇒ 0-245 = 4.9t + 0.5×(-9.8)×t²

⇒ -245 = 4.9t - 4.9t²

⇒ 4.9t² -4.9t -245 =0

Solving it, we get  t = 7.59s

v = u + at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/s

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A bowling ball with a mass of 7.0kg strikes a pin that had a mass of 2.0kg the pin flies forward with a velocity of 6.0m/s, and
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The conservation of momentum P states that the amount of momentum remains constant when there are not external forces.

We don't have external forces, so:

P_0 = P_1\\m_bv_{0b}+m_pv_{0p}=m_bv_{1b}+m_pv_{1p}\\

Where:

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  • v_{0b}\quad and\quad v_{0p} the initial velocities of the bowling ball and the pin.
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Solving for v0b:

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