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Nimfa-mama [501]
3 years ago
9

How are convalent molecules named?

Chemistry
2 answers:
stellarik [79]3 years ago
6 0

Covalent compounds are named by using numerical prefixes to identify the number of atoms in the molecule. E.g. Mono, Di, tri, tetra, etc.

In the naming, never use mono- for the first element.

The first element keeps its name.

The second element always end in the suffix -ide.

Drop the double vowel for the prefix and the element of the second element in the compound.

Hope this helped!

atroni [7]3 years ago
4 0

Answer: convalent compounds share two elements in forming a BOND between atoms

Explanation: if you dont believe me look it up and google will give you the same answer

please give brainliest

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Calculate the standard reaction Gibbs free energy for the following cell reactions: (a) 2 Ce41(aq) 1 3 I2(aq) S 2 Ce31(aq) 1 I32
Law Incorporation [45]

<u>Answer:</u>

<u>For a:</u> The standard Gibbs free energy of the reaction is -347.4 kJ

<u>For b:</u> The standard Gibbs free energy of the reaction is 746.91 kJ

<u>Explanation:</u>

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_{cell}           ............(1)

  • <u>For a:</u>

The given chemical equation follows:

2Ce^{4+}(aq.)+3I^{-}(aq.)\rightarrow 2Ce^{3+}(aq.)+I_3^-(aq.)

<u>Oxidation half reaction:</u>   Ce^{4+}(aq.)\rightarrow Ce^{3+}(aq.)+e^-       ( × 2)

<u>Reduction half reaction:</u>   3I^_(aq.)+2e^-\rightarrow I_3^-(aq.)

We are given:

n=2\\E^o_{cell}=+1.08V\\F=96500

Putting values in equation 1, we get:

\Delta G^o=-2\times 96500\times (+1.80)=-347,400J=-347.4kJ

Hence, the standard Gibbs free energy of the reaction is -347.4 kJ

  • <u>For b:</u>

The given chemical equation follows:

6Fe^{3+}(aq.)+2Cr^{3+}+7H_2O(l)(aq.)\rightarrow 6Fe^{2+}(aq.)+Cr_2O_7^{2-}(aq.)+14H^+(aq.)

<u>Oxidation half reaction:</u>   Fe^{3+}(aq.)\rightarrow Fe^{2+}(aq.)+e^-       ( × 6)

<u>Reduction half reaction:</u>   2Cr^{2+}(aq.)+7H_2O(l)+6e^-\rightarrow Cr_2O_7^{2-}(aq.)+14H^+(aq.)

We are given:

n=6\\E^o_{cell}=-1.29V\\F=96500

Putting values in equation 1, we get:

\Delta G^o=-6\times 96500\times (-1.29)=746,910J=746.91kJ

Hence, the standard Gibbs free energy of the reaction is 746.91 kJ

7 0
3 years ago
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krek1111 [17]

Answer:

only ones ik

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3 years ago
Three elements are represented by the letters A, B, and C. the three elements have the same number of valence electrons. Element
AfilCa [17]
Answer:
A- beryllium
B- calcium
C- magnesium

Explanation
NOTE: all element in group 2 have 2 balance electrons

First let’s start with B- number of electrons= number of protons which is equal to the atomic number. therefore, the answer is calcium as it’s atomic number is 20

C- magnesium will have three energy levels considering it has 12 electrons (2,8,2).

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Ability to adapt to their environment?? there isn't much context to the question /:
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N76 [4]

Answer:

Hey!

Your answer is element A

Explanation:

Using the graph, the element A's emission of radioactive particles ends approximately after 6 years...

A HALF-LIFE IS "HALF" OF THAT TIME PERIOD!

So if the radiation goes for 6 years the half-life is 6 divided by two which gives you 3 years!

The rest however have a longer half-life...

Because they all end at 14 yrs so their half-life in 7 years!

HOPE THIS HELPS!!

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