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mars1129 [50]
3 years ago
10

The negative particles inside an atom are called???

Chemistry
1 answer:
Minchanka [31]3 years ago
7 0

Answer:

electrons

Explanation:

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How many pairs are shared between the nitrogen atoms for hydrazine
morpeh [17]
<span>A full outer shell has 8 valence electrons, and since each nitrogen has only five, they both need three more to get to a full outer shell. However, since they're the same atom, and they need the same amount of electrons, they're going to form a covalent bond, where they both SHARE three (if one gave three to the other, it would be down to two and even MORE unbalanced)</span>
4 0
3 years ago
The [α] of pure quinine, an antimalarial drug, is −165. If a solution contains 86% quinine and 14% of its enantiomer (ee = 72%),
ratelena [41]

Answer : The [α] for the solution is, -118.8

Explanation :

Enantiomeric excess : It is defined as the difference between the percentage major enantiomer and the percentage minor enantiomer.

Mathematically,

\%\text{ Enantiomer excess}=\%\text{ Major enantiomer}-\%\text{ Minor enantiomer}

Given:

% major enantiomer = 86 %

% minor enantiomer = 14 %

Putting values in above equation, we get:

\%\text{ Enantiomer excess}=86\%-14\%=72\%

\text{ Enantiomer excess}=\frac{72}{100}=0.72

Now we have to calculate the [α] for the solution.

[\alpha]=\text{Enantiomer excess}\times [\alpha]_{Pure}

[\alpha]=0.72\times -165

[\alpha]=-118.8

Thus, the [α] for the solution is, -118.8

4 0
3 years ago
38 An aluminum sample has a mass of 80.01 g and a density of 2.70 g/cm3. According to the data, to what number of significant fi
Furkat [3]
The answer is (3) 3. The calculation rule of significant figures is when multiplication and division, the significant figures of result is equal to the least of the numbers involved. The significant figure of 2.70 and 80.01 is 3 and 4.
3 0
3 years ago
Read 2 more answers
Why doesn't light get absorbed
ziro4ka [17]
It isn't a materialistic object.

6 0
3 years ago
It takes 167 s for an unknown gas to effuse through a porous wall and 99 s for the same volume of n2 gas to effuse at the same t
irakobra [83]

Answer : The molar mass of the unknown gas will be 79.7 g/mol


Explanation : To solve this question we can use graham's law;


Now we can use nitrogen as the gas number 2, which travels faster than gas 1;

So, 167 / 99 = 1.687 So the nitrogen gas is 1.687 times faster that the unknown gas 1

We can compare the rates of both the gases;


So here, Rate of gas 2 / Rate of gas 1 = \sqrt{(molar mass 1 / molar mass 2)}

Now, 1.687 = square root [\sqrt{(molar mass 1) / (28.01 g/mol N_{2})} ]


When we square both the sides we get;


2.845 = (molar mass 1) / (28.01 g/mol N2)


On rearranging, we get,


2.845 X (28.01 g/mol N2) = Molar mass 1

So the molar mass of unknown gas will be = 79.7 g/mol

3 0
3 years ago
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