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mars1129 [50]
4 years ago
10

The negative particles inside an atom are called???

Chemistry
1 answer:
Minchanka [31]4 years ago
7 0

Answer:

electrons

Explanation:

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How many neutrons does element X have if its atomic number is 29 and its mass number is 99?
stira [4]
Number of neutrons = mass number - atomic number

= 99-29 = 70 
4 0
4 years ago
8KCIO3 +1C12H22011
docker41 [41]

3.2 g KClO3

Explanation:

1.1 g C12H22O11 × (1 mol C12H22O11/342.3 g C12H22O11)

= 0.0032 mol C12H22O11

0.0032 mol C12H22O11 × (8 mol KClO3/1 mol C12H22O11)

= 0.026 mol KClO3

Therefore, the minimum amount of KClO3 needed is

0.026 mol KClO3 × (122.55 g KClO3/1 mol KClO3)

= 3.2 g KClO3

5 0
3 years ago
1-Are natural resources renewable or nonrenewable?
vivado [14]

Answer:

1- Natural sources are renewable with time

2- To refrain from over usage of products on unnecessary things

3- An example of poor soil management is using the soil with the most minerals to put houses on instead of farming with

8 0
3 years ago
The most powerful respiratory stimulus for breathing in a healthy person is ________. A. pH (alkalosis) B. loss of oxygen in tis
blsea [12.9K]

Answer:

D. increase of carbon dioxide

Explanation:

Breathing is automatic and is controlled subconsciously by respiratory center at base of brain. It continues during the time of the sleep and even when the person is not in conscious. Sensory organs in brain and in aorta and  the carotid arteries monitor blood and sense the oxygen and the carbon dioxide levels. <u>Usually, increased concentration of the carbon dioxide is the strongest stimulus for the breathing to occur more deeply and more frequently.  </u>

When carbon dioxide concentration in the blood is high, the brain increases the frequency and the depth of breaths.

7 0
4 years ago
The half-life of cobalt-60 is 5. 20 yr. how many milligrams of a 2. 000 mg sample remain after 6. 55 years?
Stels [109]

0.84 milligrams of a 2. 000 mg sample remain after 6. 55 years, according to radioactive decay.

Given data,

t\frac{1}{2} of Co-60 = 5.20years

amount of sample = 2.000mg initially = 0.002grams

According to radioactive decay,

N_{t} = N_{0}e^{-λt}

(N_{0} - 0.002 )λ = \frac{0.693}{t\frac{1}{2} } = \frac{0.693}{5.20}  = 0.133

According to radioactive decay,

N_{t} = N_{0}e^{-λt}

lnN_{t}  = lnN_{0} - λt

lnN_{t} = ln0.002 - (0.133×6.55)

       = -6.21 - 0.87 = -7.08 = 0.00084g = 0.84mg

Therefore, 0.84 milligrams of a 2. 000 mg sample remain after 6. 55 years.

Learn more about radioactive decay here:

brainly.com/question/1770619

#SPJ4

5 0
2 years ago
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