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slava [35]
3 years ago
9

A Cylinder with a volume of 27π in 3 and a height of 3 in. What is the radius?

Mathematics
1 answer:
Ronch [10]3 years ago
7 0

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Surface Areas and Volume.

==> Volume of Cylinder = πr^2h

==> 27π = πr^2(3)

==> 27 = r^2 (3)

==> r^2 = 9

==> r = 3 inch

hence the radius is 3 inches.

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\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\

\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
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\end{array}\\\\
-------------------------------\\\\
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\\\\\\
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\bf \\\\
-------------------------------\\\\
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