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photoshop1234 [79]
3 years ago
15

A balloon that has a volume of 9.45L of helium is released at the ground where the pressure is 760mmHg. What is the volume of th

e balloon when it rises in the atmosphere to a place where pressure is 640mmHg
Chemistry
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

What is the volume of the balloon when it rises in the atmosphere to a place where pressure is 640mmHg

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Which of these is not a structural adaptation? A) Horns B) Thick white fur C) Seasonal migration D) A long beak
Snezhnost [94]

Answer:

c) Seasonal migration

Explanation:

Because A, B and C are all examples of structural adaptations. And seasonal migration is not something that is in an animals structure but is instinct.

Have a great day!

6 0
3 years ago
Determine the ΔH for the following reaction 2NH3 + 5/2O2 = 2NO(g) + 3 H2O(g)
beks73 [17]

The enthalpy change, ΔH for the following reaction 2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g) is -452.76 kJ.

<h3>What is enthalpy change, ΔH, of a reaction?</h3>

The enthalpy change of a reaction is the heat changes that occurs when a reaction proceeds to formation of products.

  • Enthalpy change, ΔH = ΔH of products - ΔH of reactants

The equation of the reaction is given below

2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g)

\Delta{H_{f}\:of\:NO = 90.25 kJ; \Delta{H_{f}\:of\:H_{2}O =-241.82kJ;  \Delta{H_{f}\:of\:NH_{3} =-46.1 kJ;  \Delta{H_{f}\:of\:O_{2} =0

\Delta{H_{f}\:of\:rxn = (90.25*2)+(-241.82*3)-( -46.1*2)= -452.76\:kJ

Therefore, the enthalpy change, ΔH for the following reaction 2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g) is -452.76 kJ.

Learn more about enthalpy change at: brainly.com/question/14047927

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4 0
2 years ago
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Name the elements present in a) zinc sulphide b) sodium oxide​
Vinil7 [7]

Answer:

a) zinc, sulphur, oxygen

b) sodium, oxygen

5 0
3 years ago
When a person walks into the water, it appears that their feet are separated 1 point
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6 0
3 years ago
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For the reaction: 2 A+B 3 C the rate of disappearance of B was 0.30 M/s. What is the rate of disappearance of A and the rate of
GenaCL600 [577]

Answer:

rA = 0.60 M/s

rC = 0.90 M/s

Explanation:

Let's consider the following reaction:

2 A+B ⇒ 3 C

The rate of each substance can be calculated like the change in its concentration divided by the change in time. Given the rate must always be positive, we add a minus sign before the reactants change in concentration.

rA=-\frac{\Delta[A] }{\Delta t}

rB=-\frac{\Delta[B] }{\Delta t}

rC=\frac{\Delta[C] }{\Delta t}

The rate of the reaction is equal to the rate of each substance divided by its  stoichiometric coefficient.

r= \frac{rA}{2} =\frac{rB}{1} =\frac{rC}{3}

The rate of disappearance of B is 0.30 M/s.

The rate of disappearance of A is:

\frac{rA}{2} =\frac{rB}{1}\\rA = 2 \times rB = 2 \times 0.30 M/s = 0.60 M/s

The rate of appearance of C is:

\frac{rB}{1} =\frac{rC}{3}\\rC = 3 \times rB = 3 \times 0.30 M/s = 0.90 M/s

5 0
3 years ago
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