Answer:
-3
Explanation:
The oxidation state or oxidation number of an atom is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.
The complex anion here is [Cr(CN)6]3-.
Now, as the oxidation state of CN or cyanide ligand is -1, and if we suppose the oxidation state of Cr to be 'x', then; x - 6 = -3 (overall charge on the anion),
so x= +3. Hence the oxidation state of Chromium in this complex hexacyanochromium (III) anion comes out to be -3.
.
<h3><u>Answer;</u>
</h3>
= 607.568 Torr
<h3><u>Explanation;
</u></h3>
1 in of mercury is equivalent to 25.4 Torr
Therefore;
23.92 InHg will be equal to;
23.92 × 25.4
<u>= 607.568 Torr</u>
Answer: The approximate molecular mass of the polypeptide is 856 g/mol
Explanation:
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
Or,
where,
= osmotic pressure of the solution = 4.19 torr
i = Van't hoff factor = 1 (for non-electrolytes)
Mass of solute (polypeptide) = 0.327 g
Volume of solution = 1.70 L
R = Gas constant = 
T = temperature of the solution = ![26^oC=[273+26]K=299K](https://tex.z-dn.net/?f=26%5EoC%3D%5B273%2B26%5DK%3D299K)
Putting values in above equation, we get:
Hence, the molar mass of the polypeptide is 856 g/mol
Answer:
Option (3)
Explanation:
Wind energy is directly derived from the wind. In the places where wind blowing is quite frequent, there wind mills are being set up, and the turbines in it rotates due to the prevailing wind. Due to this continuous motion of turbines, it collects the wind energy and it is being transferred into electrical energy.
It is cost-effective and does not produce any kind of pollution and is completely a renewable energy, that it can generated again and again.
It does have certain drawbacks also, because <u>the area may sometime do not experience constant wind, due to which it cannot store energy. So frequent wind blowing areas are the best place to set up windmills</u>.
Thus, the correct answer is option (3)
Answer:
0.600 g/cm³
Explanation:
Step 1: Given data
- Height of the cylinder (h): 6.62 cm
- Diameter of the cylinder (d): 2.34 cm
- Mass of the cylinder (m): 17.1 g
Step 2: Calculate the volume of the cylinder
First, we have to determine the radius, which is half of the diameter.
r = d/2 = 2.34 cm/2 = 1.17 cm
Then, we use the formula for the volume of the cylinder.
V= π × r² × h
V= π × (1.17 cm)² × 6.62 cm
V = 28.5 cm³
Step 3: Calculate the density (ρ) of the sample
The density is equal to the mass divided by the volume.
ρ = m/V
ρ = 17.1 g/28.5 cm³
ρ = 0.600 g/cm³
