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Soloha48 [4]
3 years ago
5

What are the solutions to the following equation? select all that apply. 0= x^2 - x + 5

Mathematics
1 answer:
Dominik [7]3 years ago
7 0

Answer:

I think it is a and f i could be wrong

Step-by-step explanation:

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“Solve the equation. Determine if it is undefined or not.”
lozanna [386]

Answer:  a) No Solution

               b) Infinite Solutions  (All Real Numbers)

<u>Step-by-step explanation:</u>

4(g + 8) = 7 + 4g

4g + 32 = 7 + 4g      <em>distributed 4 into g + 8</em>

        32 = 7             <em> subtracted 4g from both sides</em>

Since the statement is false because 32 ≠ 7, then there is NO SOLUTION

-4(-5h - 4) = 2(10h + 8)

20h + 16  = 20h + 16       <em>distributed</em>

           16  =           16        <em>subtracted 20h from both sides</em>

Since the statement is true because 16 = 16, then there are INFINITE SOLUTIONS so x can be all real numbers.

8 0
3 years ago
What is the simplified value of the expression below?
polet [3.4K]

Answer:

C. 9

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
Solve the equation <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B10%7D%20%2B8%3D17" id="TexFormula1" title="\frac{n}{10} +8
jonny [76]
Its 90 because 90 divided by 10 simplifies down to 9, and 9+8=17
3 0
3 years ago
What radius of a circle is required to inscribe an equilateral triangle with an area of 270.633 cm2 and an altitude of 21.65 cm?
adoni [48]
1. 
<span>All three angles are equal and their sum is 180. </span>
<span>3 (3x-12) = 180 </span>
<span>9x -36 = 180 </span>
<span>9x = 180+36 </span>
<span>9x = 216 </span>
<span>x = 216/ 9 = 24 </span>

<span>2. </span>
<span>Area of an equilateral triangle = (sqrt(3)/4 ) s^2 = 270.633 </span>
<span>s^2 = 270.633 / [ sqrt(3) /4] </span>
<span>s^2 = (4)(270.633) / sqrt(3) </span>
<span>s^2 = 625 </span>
<span>s = 25 (side) </span>

<span>Follow the procedure in the link: we don't need the altitude. </span>
<span>r = 25/sqrt(3) =14.43 

</span>
7 0
3 years ago
Read 2 more answers
Please HELLLLP! I will mark brainliest!
Anuta_ua [19.1K]
36-(b^2+c^2-2bc)=36-(b-c)^2=6^2-(b-c)^2= (6+b-c)[6-(b-c)]=(6+b-c)(6-b+c)
4 0
3 years ago
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