The picture shows a turgor pressure demonstration using stalks of celery in different salt solutions. Which of these shows the c
elery stalks in order from the one with the most turgor pressure to the one with the least turgor pressure?
Group of answer choices
T,Q,R,S
Q,T,S,R
Q,R,S,T
S,R,Q,T
Group of answer choices
T,Q,R,S
Q,T,S,R
Q,R,S,T
S,R,Q,T
1 answer:
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Answer:
The correct answer would be 48 percent.
It can be solved by using the Hardy-Weinberg equation.
p² + 2pq+ q² = 1
p + q = 1
where, p² represents homozygous dominant's frequency that is, SS in this case,
q² represents homozygous recessive's frequency that is, ss in this case,
2pq represents heterozygous dominant's frequency that is, Ss in this case.
p represents dominant allele's frequency and q represents the recessive allele's frequency.
Now, the percentage of homozygous recessive or short stems is 35%. Therefore, the frequency of homozygous recessive would be 0.35.
Thus, the value of q² = 0.35
So, q = = 0.59 which is approximately equals to 0.6.
As p + q = 1 so, q = 1 - 0.6 = 0.4
The frequency of heterozygous (Ss) = 2pq = 2(0.6)(0.4) = 0.48
Hence, the frequency of heterozygous would be 48 percent.