Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
Answer:
0
Step-by-step explanation:
it doesn't slope, it goes in a straight line, moving on the x-axis
Vcylinder-Vsphere=water
Vcylinder=hpir^2
Vsphere=(4/3)pir^3
given
cylinderradius=30 and h=100
Vcylinder=100pi30^2=100pi900=90000pi
let's leave it in terms of pi for more exactness
sphereradius=12
Vsphere=(4/3)pi12^3=2304pi
cylinder-sphere=90000pi-2304pi=87696pi
using pi=3.14
water=275365.44 cubic cm
last option is corrrect
Rules for adding: if the bases are the same you can add them, and subtracting happens in a fraction
