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zlopas [31]
3 years ago
15

Please help go over my work

Chemistry
2 answers:
maxonik [38]3 years ago
4 0

Answer:

it's A

Explanation:

......................

beks73 [17]3 years ago
3 0
It’s a idjdjjdjdjjfkdkdkdjjdfjjdhshdh
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A can of soda at 27oC (mass of 310g) is placed in a freezer with a temperature of -14oC. How much energy must be removed for the
kipiarov [429]

Answer:

3

Explanation:

4 0
2 years ago
8. Bring the balloon in contact with the wall. What happens to the charges in the wall?
Ne4ueva [31]

When the charged balloon is brought near the wall, it repels some of the negatively charged electrons in that part of the wall. Therefore, that part of the wall is left repelled.

<u>Explanation</u>:  

  • Balloons don't stick to walls. However, if you rub the balloon on an appropriate piece of material such as clothing or a wall, electrons are pulled from the other material to the balloon.
  • The balloon now as more electrons than normal and therefore has an overall negative charge. Two balloons like this will repel each other.
  • The other material now has an overall positive charge. Because opposite charges attract, the balloon will now appear to stick to the other material. If you didn't rub the balloon first, it's charge would be neutral and it wouldn't stick to the wall.
7 0
3 years ago
The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151
vitfil [10]

Answer:-  The natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

Let's plug in the values in the formula:

151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

-0.957243=-2.001383n

negative sign is on both sides so it is canceled:

0.957243=2.001383n

n=\frac{0.957243}{2.001383}

n=0.478

The abundance of ^1^5^1_E_u is 0.478 which is 47.8%.  

The abundance of ^1^5^3_E_u is = 1-0.478

= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


3 0
2 years ago
You are cooking dinner using a metal pan. When you pick up the pan,the handle burns your hand. Which form of thermal energry tra
VLD [36.1K]

Answer:

Conduction

Explanation:

4 0
2 years ago
Read 2 more answers
What is the molarity of a 9.13 L soda that contains 13.83 of sugar?
choli [55]

Answer:

1.52 M

Explanation:

Molarity of a solution is calculated as follows:

Molarity = number of moles (n) ÷ volume (V)

Based on the information given in this question,

Volume of soda (V) = 9.13 L

number of moles = 13.83 mol

Molarity = 13.83 ÷ 9.13

Molarity = 1.52 M

7 0
2 years ago
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