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Setler79 [48]
2 years ago
10

The world's fastest production sportscar has a top speed of 415 kmh-1(a)Convert this speed to ms-1.[ 1](b)The distance from Lond

on to Edinburgh is 403 miles. There are 1609 metres in a mile.How long would it take the car to travel from London to Edinburgh if it was able to travel at top speed? Give your answer to the nearest minute.[ 4](c)The International Space Station travels at 7.66 km s-1. In the time it takes the car to travel from London to Edinburgh, how far will the International Space Station have travelled?[ 2](d)Speed and velocity have different definitions in physics –yet both are measured in ms-1. Explain the difference
Physics
1 answer:
Alex73 [517]2 years ago
3 0

Answer:

(a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

Explanation:

Given that,

Top speed = 415 km/h

1 miles = 1609 m

(a). We need to calculate the speed in m/s

Using conversion of km/h to m/s

v=415\ km/h

v=415\times\dfrac{5}{18}

v=115.28\ m/s

(b). We need to calculate the distance from London to Edinburgh in km

Using conversion for distance

d=403\ miles

Distance in meter,

d=403\times1609

d=648427\ m

d=648.427\ km

We need to calculate the time

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{648.427}{415}

t=1.56\ h

t=1\ hours 34\ min

t= 94\ min

(c). Speed v' =7.66 km/s

v'=7660 m/s

In the time it takes the car to travel from London to Edinburgh,

We need to calculate the distance

Using formula of distance

d'=v'\times t

Put the value into the formula

d'=7660\times94\times60

d'=43202400\ m

d'=43202.400\ km

(d). Speed :

Speed is equal to the distance divided by time.

It is scalar quantity.

Velocity :

Velocity is equal to the displacement divided by time.

It is vector quantity.

Hence, (a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

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Following your push the ball rolls down the lane at 4.2m/s. What is the net force on the ball as it rolls down the lane at the constant speed?
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At one point in the circuit, there is an LED and a resistor in parallel with one another. If you measure the voltage drop across
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Answer:

C. The voltage drop across the resistor is 2.1V and nothing about the current through the resistor.

Explanation:

When connected in parallel, voltage across the resistances are the same. So if 2.1V was dropped across the LED then 2.1V was also dropped across the resistor. However, this tells us nothing about the current through the resistor. We can find the current across the resistor if we know the resistance of the resistor, but that's about it.

If it were a series connection, then the current would have been the same, but the voltage drop were another story.

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A field measuring 12 meters by 16 meters is to have a brick paver walkway installed all around it, increasing the total area to
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Answer:

1.5 m

Explanation:

Length. L = 12 m

Width, W = 16 m

Area, A = 12 x 16 = 192 m^2

Let the width of pavement be d.

The new length, L' = 12 + 2d

the new width, W' = 16 + 2d  

New Area, A' = L' x W' = (12 + 2d)(16 + 2d) = 192 + 56 d + 4d^2

Difference in area = A' - A

285 =  192 + 56 d + 4d^2 - 192

93 =  56 d + 4d^2

4d^2 + 56 d - 93 = 0

d = \frac{-56\pm \sqrt{56^{2}+4\times 4\times 93}}{8}

d=\frac{-56\pm 87.72}{8}\

d = 1.5 m

Thus, the width of the pavement is 1.5 m.

6 0
3 years ago
A person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. Use the vertical motio
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Answer:

3.25 seconds

Explanation:

It is given that,

A person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. The equation for his motion is as follows :

h=-16t^2+vt+s

Where

s is the height in feet

For the given condition, the equation becomes:

h=-16t^2+50t+7

When it hits the ground, h = 0

i.e.

-16t^2+50t+7=0

It is a quadratic equation, we find the value of t,

t = 3.25 seconds and t = -0.134 s

Neglecting negative value

Hence, for 3.25 seconds the baseball is in the air before it hits the ground.

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Answer:

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