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Mariulka [41]
1 year ago
11

Electrical energy is used to turn the blades of a fan. The amount of energy transformed is seen here: 750 j electrical energy is

transformed into 400 j kinetic or mechanical energy. What happened to the remaining 350 j of energy?.
Physics
1 answer:
MAVERICK [17]1 year ago
4 0

Here is the energy that is left after the quantity of energy is transformed: 750 j of electrical energy is changed into 400 j of kinetic or mechanical energy, which is then turned into 0.32 j of efficient energy.

To run the fan, electrical energy is utilized.

Here, under the specified circumstances, 750 J of electrical energy is utilized to operate the fan, which is transformed into 400 J of kinetic energy. As a result, 350 J of energy is wasted due to various frictional and resistive losses.

Therefore, we may conclude that only 400 J of the 750 J available energy is used to power the fan, with the remaining energy being wasted as a result of friction.

Additionally, we can state that this fan's effectiveness will be

n = Useful ÷ Total

n = 400 ÷ 750

n = 8 ÷ 25

n = 0.32

Learn more about energy at

brainly.com/question/15915007?referrer=searchResults

#SPJ4

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What is the name of the theory describing how the lithosphere is broken into segments, or plates, which "float" on the asthenosp
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Answer:

C. Plate Tectonics

Explanation:

The theory of plate tectonics is when the lithosphere is separated into plates. These plates move over or float over the asthenosphere. The movement of these plates cause earthquakes and can interact with the volcanic activity.

4 0
3 years ago
Please help me on question 3a and 3b.<br><br>Thanks! ​
Sonbull [250]

(a) The frequency of water wave is 2 Hz.

(b) The wave speed of the water wave is 3.6 m/s.

<u>Explanation:</u>

(a) It is known that completion of one complete wave in 1 second is defined as frequency of 1 HZ. So here there are 120 waves crossing the boat in 1 minute. So the frequency of the water wave will be

            Frequency =\frac{\text { Number of waves }}{\text { Time in seconds }}

As the time is 1 minute which is equal to 60 seconds and the number of waves is given as 120 then the frequency of the water wave is

         \text { Frequency }=\frac{120}{60}=2 \mathrm{Hz}

So the frequency of water wave is 2 Hz.

(b) Then if the wavelength of the water wave is 1.8 m with a frequency of 2 Hz, then speed of the wave can be determined as the product of wavelength with frequency.

So Speed = Frequency × Wavelength

Speed = 2 × 1.8 = 3.6 m/s.

So the speed of the water wave is 3.6 m/s.

7 0
3 years ago
Water having a density of 1000 kg/m^3 is flowing with a velocity of 3 m/s through a round pipe. There is a restriction within th
Fofino [41]

Answer:

12 m/s

Explanation:

Using the continuity equation, which is an extension of the conservation of mass law

ρ₁A₁v₁ = ρ₂A₂v₂

where 1 and 2 indicate the conditions at two different points of flow, in this case, point 1 is any normal position in the pip and point 2 is the conditions at the restriction.

ρ = density of the fluid flowing; note that the density of the fluid flowing (water) is constant all through the fluid's flow

A₁ = Cross sectional Area of the pipe at point 1 = (πD₁²/4)

A₂ = Cross sectional Area of the pipe at the restriction = (πD₂²/4)

v₁ = velocity of the fluid flowing at point 1 = 3 m/s

v₂ = velocity of the fluid flowing at The restriction = ?

ρ₁A₁v₁ = ρ₂A₂v₂

Becomes

A₁v₁ = A₂v₂ (since ρ₁ = ρ₂)

(πD₁²/4) × 3 = (πD₂²/4) × v₂

3D₁² = D₂² × v₂

But

D₂ = (D₁/2)

And D₂² = (D₁²/4)

3D₁² = D₂² × v₂

3D₁² = (D₁²/4) × v₂

(D₁²/4) × v₂ = 3D₁²

v₂ = 4×3 = 12 m/s

8 0
3 years ago
If a rod attached to the approaching charge if the rod consists of "stiff" spring-like bonds for which atoms undergo small oscil
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Answer: hello options related to your question is missing attached below is the missing part of your question

answer: No charge of the length of the bonds expected because the rod did not touch the charge source ( option A )

Explanation:

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5 0
3 years ago
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Jet001 [13]

Answer:

The fourth graph is the answer

Explanation:

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y>x+2

For the first inequality all points at or below the graph of y are solutions, and for the second inequality all the points above the graph of y are the solutions. So, the solution to these inequalities are points that are above the graph of y>x+2 and below the graph of y\leq 2x+4. The shaded region in the fourth graph satisfies these conditions.

<em>Looking at other choices, we see that the first two graphs do not even represent the graphs of our inequalities, and the third graph does represent the inequalities but shades the wrong region. </em>

P.S: the graph of the inequality y>x+2  is dashed because   y is "greater than" and not "equal to" x+2, so this indicates that the values on the line y=x+2 are not included. And the graph of the inequality y\leq 2x+4 is a solid line because y is "less than or equal to" 2x+4, so we are including the values on the line y=2x+4, and that's why it's solid.

6 0
3 years ago
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