The distance formula:d = v i · t + a · t² / 2Sir G.: ( v i = 0 )
d G = 0 + 0.3 · t² / 2Sir A. : d A = 0 + 0.2 t² / 288 m = 0.3 t² / 2 + 0.2 t² / 2 / · 2 ( multiple both sides by 2 )176 = 0.3 t² + 0.2 t²176 = 0.5 t²t² = 176 : 0.5t² = 352t = √352t = 18.76 sd G. = 0.3 · 18.76² / 2 = 0.3 · 352 / 2 = 52.8 mAnswer: The knights collide at 52.8 m relative to Sir George`s starting point.
Your answer would be
B. 7.3 KG
Explanation:
a) The angular speed omega is given defined as
omega = #rev/period = 1 rev/(0.6 s) = 1.7 rev/s
= (1.7 rev/s)×(2pi/rev) = 10.5 rad/s
b) v = (omega)×r
= (10.5 rad/s)(0.110 m)
= 1.16 m/s
Answer:
(Equation 10.3. 2): RS=R1+R2+R3+R4+R5=20Ω+20Ω+20Ω+20Ω+10Ω=90Ω
Explanation:
pure definition :
kilo means 1000 (thousand).
so, a km or kilometer is 1000 m or meter.
2000 km = 2000 × 1000 m = 2,000,000 meters
