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Talja [164]
3 years ago
10

PLEASE HELP THIS IS A TEST I WAS SUPPOSE TO DO 8 HOURS AGO.

Engineering
1 answer:
nordsb [41]3 years ago
7 0
The only dimension you gave me is the width so I will work with that. If it’s asking for a smaller drawing than what is giving then the width will be 1/4 inch but if you’re saying the drawing is bigger then the width will be 4 inches
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Write a Pig script and run it in local mode on this data to find out the top 10 states according to the land area. Since you wan
ELEN [110]

Explanation:

Apache Pig script execution modes

Local mode: In 'local mode', you can run the pig script on the local file system. In this case, you don't need to store the data in the Hadoop HDFS file system, instead you can work with the data stored in the local file system.

MapReduce mode: In 'MapReduce mode', the data must be stored in the HDFS file system and you can process the data with the help of pig script.

Apache Pig Script in MapReduce mode

Let's say our task is to read data from a data file and display the required contents in the terminal as output.

The sample data file contains the following data:

Txt information file - Apache Pig Script - Edureka

Save the text file with the name 'information.txt'

The sample data file contains five First Name, Last Name, Mobile Number, City, and Profession columns separated by the tab key. Our task is to read the contents of this HDFS file and display all the columns of these records.

To process this data using Pig, this file must be present in Apache Hadoop HDFS.

Command: hadoop fs –copyFromLocal /home/edureka/information.txt / edureka

3 0
3 years ago
A rigid tank having 25 m3 volume initially contains air having a density of 1.25 kg/m3, then more air is supplied to the tank fr
Hoochie [10]

Answer:

\Delta m = 102.25\,kg

Explanation:

The mass inside the rigid tank before the high pressure stream enters is:

m_{o} = \rho_{air}\cdot V_{tank}

m_{o} = (1.25\,\frac{kg}{m^{3}} )\cdot (25\,m^{3})

m_{o} = 31.25\,kg

The final mass inside the rigid tank is:

m_{f} = \rho \cdot V_{tank}

m_{f} = (5.34\,\frac{kg}{m^{3}} )\cdot (25\,m^{3})

m_{f}= 133.5\,kg

The supplied air mass is:

\Delta m = m_{f}-m_{o}

\Delta m = 133.5\,kg-31.25\,kg

\Delta m = 102.25\,kg

4 0
3 years ago
13–27. The conveyor belt is moving downward at 4 m>s. If the coefficient of static friction between the conveyor and the 15-k
Feliz [49]

Answer:

See explanation for step by step procedure to get answer.

Explanation:

Given that:

The conveyor belt is moving downward at 4 m>s. If the coefficient of static friction between the conveyor and the 15-kg package B is ms = 0.8, determine the shortest time the belt can stop so that the package does not slide on the belt.

See the attachments for complete steps to get answer.

4 0
4 years ago
Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You wi
yan [13]

Answer:

The filled in codes are

1) private static int[] arr;

2)  int arr[] = new int[size_of_array];

        int increment = 100;

        for (int i = 0; i < size_of_array; i++) {

       arr[i] = increment * i;

       }

      return arr;

3) for (int i = 0; i < myArray.length; i++) {

      System.out.println(myArray[i]);

4)  OneDimensionalArrays result = new OneDimensionalArrays();

    result.createIntegers(num);

    result.printArray(arr);

Explanation:

Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You will complete the class by filling in code wherever you see the comment:

//******* FILL IN CODE *********

import java.util.Scanner;

public class OneDimensionalArrays {

   

   int[] createIntegers(int size_of_array)

   {

      //*******  FILL IN CODE *********

      // Your code will create an array of ints as large as specified in size_of_array

      // Fill the array in with the values: 0, 100, 200, 300, ....

      // Return the array that you just created

   }

   void printArray(int[] myArray)

   {

      //*******  FILL IN CODE *********

       // Print out your array with one number per line.  Get the size of the

       // array from the "myArray" parameter (no hard coding the size)

   }

   public static void main(String[] args) {

       Scanner keyboard = new Scanner(System.in);

       

       System.out.println("Enter size of array to create: ");

       int num = keyboard.nextInt();

       //*******  FILL IN CODE *********

       // Construct an instance of the OneDimensionalArrays class

       // Using this object instance, call createIntegers to create

       // an array of integers.  Don't forget to save the results

       // Then call the printArray method to print out the contents

       // of your array.

       }

}

Completed Code when filled in looks this way below:

import java.util.Scanner;

public class OneDimensionalArrays {

  private static int[] arr;

  int[] createIntegers(int size_of_array) {

       int arr[] = new int[size_of_array];

       int increment = 100;

       for (int i = 0; i < size_of_array; i++) {

             arr[i] = increment * i;    

       }

       return arr;

   }

   void printArray(int[] myArray) {

       for (int i = 0; i < myArray.length; i++) {

           System.out.println(myArray[i]);          

       }

   }

   public static void main(String[] args) {

       Scanner keyboard = new Scanner(System.in);

       System.out.println("Enter size of array to create: ");

       int num = keyboard.nextInt();

       OneDimensionalArrays result = new OneDimensionalArrays();

       result.createIntegers(num);

       result.printArray(arr);

   }

}

7 0
3 years ago
Assume that each atom is a hard sphere with the surface of each atom in contact with the surface of its nearest neighbor. Determ
deff fn [24]

Answer:

The classification of the concern is listed in the interpretation segment below.

Explanation:

(a)...

<u>Simple cubic lattice</u>

<u />a=2r

Now,

The unit cell volume will be:

=a^3

=(2r)^3

=8r^3

At one atom per cell, atom volume will be:

=(1)\times (\frac{4 \pi r^3}{3})

Then the ratio will be:

Ratio=\frac{\frac{4 \pi r^3}{3}}{8r^3}\times 100 \ percent

        =52.4 \ percent

(b)...

<u>Diamond lattice</u>

The body diagonal will be:

d=8r=a\sqrt{3}

       a=\frac{8}{\sqrt{3}}r

The unit cell volume will be:

=a^1

=(\frac{8r}{\sqrt{3}})^1

At eight atom per cell, the atom volume will be:

=8(\frac{4 \pi r^1}{3})

Then the Ratio will be:

Ratio=\frac{8(\frac{4 \pi r^1}{3})}{(\frac{8r}{\sqrt{3}})^1}\times 100 \ percent

        =34 \ percent

Note: percent = %

5 0
3 years ago
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