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sveticcg [70]
3 years ago
10

Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You wi

ll complete the class by filling in code wherever you see the comment:
Engineering
1 answer:
yan [13]3 years ago
7 0

Answer:

The filled in codes are

1) private static int[] arr;

2)  int arr[] = new int[size_of_array];

        int increment = 100;

        for (int i = 0; i < size_of_array; i++) {

       arr[i] = increment * i;

       }

      return arr;

3) for (int i = 0; i < myArray.length; i++) {

      System.out.println(myArray[i]);

4)  OneDimensionalArrays result = new OneDimensionalArrays();

    result.createIntegers(num);

    result.printArray(arr);

Explanation:

Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You will complete the class by filling in code wherever you see the comment:

//******* FILL IN CODE *********

import java.util.Scanner;

public class OneDimensionalArrays {

   

   int[] createIntegers(int size_of_array)

   {

      //*******  FILL IN CODE *********

      // Your code will create an array of ints as large as specified in size_of_array

      // Fill the array in with the values: 0, 100, 200, 300, ....

      // Return the array that you just created

   }

   void printArray(int[] myArray)

   {

      //*******  FILL IN CODE *********

       // Print out your array with one number per line.  Get the size of the

       // array from the "myArray" parameter (no hard coding the size)

   }

   public static void main(String[] args) {

       Scanner keyboard = new Scanner(System.in);

       

       System.out.println("Enter size of array to create: ");

       int num = keyboard.nextInt();

       //*******  FILL IN CODE *********

       // Construct an instance of the OneDimensionalArrays class

       // Using this object instance, call createIntegers to create

       // an array of integers.  Don't forget to save the results

       // Then call the printArray method to print out the contents

       // of your array.

       }

}

Completed Code when filled in looks this way below:

import java.util.Scanner;

public class OneDimensionalArrays {

  private static int[] arr;

  int[] createIntegers(int size_of_array) {

       int arr[] = new int[size_of_array];

       int increment = 100;

       for (int i = 0; i < size_of_array; i++) {

             arr[i] = increment * i;    

       }

       return arr;

   }

   void printArray(int[] myArray) {

       for (int i = 0; i < myArray.length; i++) {

           System.out.println(myArray[i]);          

       }

   }

   public static void main(String[] args) {

       Scanner keyboard = new Scanner(System.in);

       System.out.println("Enter size of array to create: ");

       int num = keyboard.nextInt();

       OneDimensionalArrays result = new OneDimensionalArrays();

       result.createIntegers(num);

       result.printArray(arr);

   }

}

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aalyn [17]

Answer:

For SGID you type this

$ find . -perm /4000

For SUID you type this

$ find . -perm /2000

Explanation:

Auxiliary file permissions, that are commonly referred to as “special permissions” in Linux are needed in order to easily find files which have SUID (Setuid) and SGID (Setgid) set.

After typing

$ find directory -perm /permissions

Then type the commands in the attachment below to obtain a list of these files with SGID and SUID.

3 0
4 years ago
If block A of the pulley system is moving downward at 6 ft&gt;s while block C is moving down at 18 ft&gt;s, determine the relati
kramer

Answer:

Explanation:

The detailed steps and appropriate calculation with analysis is as shown in the attachment.

3 0
3 years ago
The function below takes a single parameter, a list of numbers called number_list. Complete the function to return a string of t
makkiz [27]

Answer:

The solution code is written in Python:

  1. def convertCSV(number_list):
  2.    str_list = []
  3.    for num in number_list:
  4.        str_list.append(str(num))
  5.    
  6.    return ",".join(str_list)
  7. result = convertCSV([22,33,44])
  8. print(result)

Explanation:

Firstly, create a function "convertCSV" with one parameter "number_list". (Line 1)

Next, create an empty list and assign it to a new variable <em>str_list</em>. (Line 2)

Use for-loop to iterate through all the number in the <em>number_list</em>.(Line 4). Within the loop, each number is converted to a string using the Python built-in function <em>str() </em>and then use the list append method to add the string version of the number to <em>str_list</em>.

Use Python string<em> join() </em>method to join all the elements in the str_list as a single string. The "," is used as a separator between the elements (Line 7) . At the end return the string as an output.

We can test the function by calling the function and passing [22,33,34] as an argument and we shall see "22,33,44" is printed as an output. (Line 9 - 10)

6 0
3 years ago
What is the mechanical advantage of a pulley with 3 support ropes?
snow_tiger [21]

Answer:

The mechanical advantage is 3 to 1

Explanation:

A frictionless pulley with three support ropes carries equal tension on each of the ropes thus;

Tension in each pulley rope = T

Total tension in the 3 ropes = 3 × T = 3·T

Direction of the tension forces on each rope = Unidirectional

Total force provided by the 3 ropes = 3·T

Therefore, a force, T, applied at the end of the rope will result in a lifting force of 3·T

Hence, the mechanical advantage = 3·T to T which is presented as follows;

Mechanical \ advantage = \dfrac{3 \cdot T}{T}  = \dfrac{3}{1}

The mechanical advantage = 3 to 1.

5 0
3 years ago
A sample of municipal sewage is diluted to 1% by volume prior to running a BOD5 analysis. After 5 days the oxygen consumption is
liberstina [14]

Answer:

BOD5 = 200 mg/L

Explanation:

given data

diluted = 1% = 0.01

time = 5 day

oxygen consumption = 2.00 mg · L−1

solution

we get here BOD5  that is BOD after 5 day

and here total volume is 100% = 1

so dilution factor is \frac{100}{1}    =  100

so BOD5 is

BOD5 = oxygen consumption × dilution factor

BOD5 = 2 × 100

BOD5 = 200 mg/L

4 0
3 years ago
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