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2 years ago

Pls help ill paypal 50 bucks if right if you explain 100 bucks

Mathematics

2 answers:

marusya05 [52]2 years ago

8 0

Answer:

blank 1: toby

blank 2: 4

Step-by-step explanation:

if im right i dont want ur money

AnnyKZ [126]2 years ago

7 0

Answer:

Clara will reach more people in 40 calls 1 by 1 more person

Step-by-step explanation:

Clara:

Her rate is 4 people in 10 calls

Using ratios

4 people x people

-------------- = -----------

10 calls 40 calls

Using cross products

4 * 40 = 10x

160 = 10x

Divide by 10

160/10 = 10x/10

16 =x

She will reach 16 people

Toby:

His rate is 3 people in 8 calls

Using ratios

3 people x people

-------------- = -----------

8 calls 40 calls

Using cross products

3 * 40 = 8x

120 = 8x

Divide by 8

120/8 = 8x/80

15 =x

He will reach 15 people

Clara will reach more people in 40 calls 16-15 = 1 by 1 more persons

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pishuonlain [190]

Answer: The answer is x^2 + 4x - 3

Step-by-step explanation:

You just combine like terms, the only ones that can combine is the 6x and -4x. You just subtract them to get the answer of x^2 + 4x - 3.

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2 years ago

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3 years ago

-5x - 15 = -200<br> solve for x

Whitepunk [10]

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Step-by-step explanation:

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2 years ago

What is the solution to this system of equations? X + 2y − z = 3 2x − y + 2z = 6 x − 3y + 3z = 4

Tomtit [17]

Answer:

Step-by-step explanation:

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2 years ago

Prove that √2 +√5 is irrational

Sindrei [870]

We have to prove that $\sqrt{2}+\sqrt{5}$ is irrational. We can prove this statement by contradiction.

Let us assume that $\sqrt{2}+\sqrt{5}$ is a rational number. Therefore, we can express:

$a=\sqrt{2}+\sqrt{5}$

Let us represent this equation as:

$a-\sqrt{2}=\sqrt{5}$

Upon squaring both the sides:

$(a-\sqrt{2})^{2}=(\sqrt{5})^{2}\\a^{2}+2-2\sqrt{2}a=5\\a^{2}-2\sqrt{2}a=3\\\sqrt{2}=\frac{a^{2}-3}{2a}$

Since a has been assumed to be rational, therefore, $\frac{a^{2}-3}{2a}$ must as well be rational.

But we know that $\sqrt{2}$ is irrational, therefore, from equation $\sqrt{2}=\frac{a^{2}-3}{2a}$ the expression $\frac{a^{2}-3}{2a}$ must be irrational, which contradicts with our claim.

Therefore, by contradiction, $\sqrt{2}+\sqrt{5}$ is irrational.

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3 years ago