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tekilochka [14]
3 years ago
7

Please help meeee?!!!!

Chemistry
1 answer:
Artemon [7]3 years ago
4 0

Explanation:

A structure in which valence electrons are depicted by dots is called a lewis structure.

For example, atomic number of oxygen is 8 and its electronic distribution is 2, 6.

Hence, the electron dot structure for O_{3} molecule is as depicted in the picture attached.

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Answer:

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3 years ago
Calculate the percentage by mass of the indicated element in the following compounds. Hydrogen in ascorbic acid, HC6H7O6, also k
Scorpion4ik [409]

Answer: The mass percent of hydrogen in ascorbic acid is 4.5 %

Explanation:

In C_6H_8O_6, there are 6 carbon atoms, 8 hydrogen atoms and 6 oxygen atoms.

To calculate the mass percent of element in a given compound, we use the formula:

\text{Mass percent of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Molar mass of ascorbic acid}}\times 100

Mass of hydrogen = 8\times 1g/mol=8g

Molar Mass of ascorbic acid =6\times 12g/mol+8\times 1g/mol+6\times 16g/mol=176g

Putting values in above equation, we get:

\text{Mass percent of hydrogen}=\frac{8g}{176}\times 100=4.5\%

Hence, the mass percent of of hydrogen in ascorbic acid is 4.5 %.

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3 years ago
Sperm whales are found in oceans around the world and are known to have the largest brain of any organism. The head of a sperm w
AlexFokin [52]
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. If 12 oranges cost $36.00, what is the cost for 20 oranges?
Olegator [25]

Answer:

60 dollars!

Explanation:

So, 12 oranges cost $36 dollars.

Now, we can solve this by finding the value for only <u>one</u> orange, then multiplying that by 20 to get our answer!

So, the value of one orange is $36 / 12 = $3. One orange is worth $3 dollars.

So, 20 oranges will be worth 20 * 3 = $60 dollars!

4 0
3 years ago
Write an expression for the equilibrium constant of each chemical equation: a. SbCl5(g)SbCl5(g) + Cl2(g) b. 2 BrNO(g)2 NO(g) + B
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Answer:

See explanation

Explanation:

Step 1: Data given

For the reaction aA + bB ⇆ cC + dD

Kc = [C]^c * [D]^d / [A]^a [B]^b

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Kc = [Cl2]*[SbCl3] / [SbCl5]

b. 2 BrNO(g) ⇄ 2NO(g) + Br2(g)

Kc = [Br2]*[NO]² / [BrNO]²

c. CH4(g) + 2 H2S(g) ⇄ CS2(g) + 4 H2(g)

Kc = [H2]^41 * [CS2] / [H2S]²*[CH4]

d. 2CO(g) + O2(g) ⇄ 2CO2(g)

Kc =  [CO2]² / [O2][CO]²

6 0
4 years ago
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