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Leokris [45]
3 years ago
14

The bond between two eatoms of the same element in which the electrons are equally shared is known as a nonpolar covalent bond.

in a water molecule,
Chemistry
1 answer:
weqwewe [10]3 years ago
8 0
I'm assuming you are supposed to complete the given statement? In a water molecule, the bonds between the hydrogen and oxygen atoms are polar covalent bonds, where electrons are unequally shared. (Oxygen is significantly more electronegative and holds onto the electrons for most of the time)
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How much energy (kJ) is required to change 0.18 mole of ice (s) at 0 C to water (l) at 0 C?
Dmitriy789 [7]

Answer:25,06 kJ of energy must be added to a 75 g block of ice.

ΔHfusion(H₂O) = 6,01 kJ/mol.

T(H₂O) = 0°C.

m(H₂O) = 75 g.

n(H₂O) = m(H₂O) ÷ M(H₂O).

n(H₂O) = 75 g ÷ 18 g/mol.

n(H₂O) = 4,17 mol.

Q = ΔHfusion(H₂O) · n(H₂O)

Q = 6,01 kJ/mol · 4,17 mol

Q = 25,06 kJ.

Explanation:

6 0
2 years ago
Consider the reaction below. Initially the concentration of SO2Cl2 is 0.1000 M. Solve for the equilibrium concentration of SO2Cl
tensa zangetsu [6.8K]

Answer:

[SO_2Cl_2] = 0.09983 M

Explanation:

Write the balance chemical equation ,

SO_2Cl_2((g) = SO_2(g) + Cl_2(g)

initial concenration of SO_2Cl_2((g)  =0.1M

lets assume that degree of dissociation=\alpha

concenration of each component at equilibrium:

[SO_2Cl_2] = 0.1-0.1\alpha

[SO_2] = 0.1\alpha

[Cl_2] = 0.1\alpha

Kc =\frac{0.1\alpha \times 0.1\alpha}{0.1-0.1\alpha}

Kc =\frac{0.1\alpha \times \alpha}{1-\alpha}

as \alpha is very small then we can neglect  1-\alpha

therefore ,

Kc ={0.1\alpha \times \alpha}

\alpha =\sqrt{\frac{Kc}{0.1}}

\alpha = 1.73 \times 10^{-3}

Eqilibrium concenration of [SO_2Cl_2] = 0.1-0.1\alpha = 0.1-0.1\times 0.00173

[SO_2Cl_2] = 0.09983 M

4 0
3 years ago
How many calories are needed to melt 30 grams of copper
hjlf
The amount of calories you weight
7 0
3 years ago
Will an object with a density of 0.999 sink or float
Semmy [17]

The density of an object determines whether it will float or sink in another substance. An object will float if it is less dense than the liquid it is placed in. An object will sink if it is more dense than the liquid it is placed in.

7 0
3 years ago
What is the overall enthalpy of reaction for the equation shown below?
Rudiy27

Answer:

ΔH₁₂ = -867.2 Kj

Explanation:

Find enthalpy for 3H₂ + O₃ => 3H₂O given ...

2H₂ + O₂ => 2H₂O      ΔH₁ = -483.6 Kj

        3O₂ => 2O₃        ΔH₂ = + 284.6 Kj

_____________________________

3(2H₂ + O₂ => 2H₂O) => 6H₂ + 3O₂ => 6H₂O       (multiply by 3 to cancel O₂)

6H₂ + 3O₂ => 6H₂O        ΔH₁ = 3(-483.6 Kj) = -1450.6Kj

          2O₃ => 3O₂           ΔH₂ = -284.6Kj              (reverse rxn to cancel O₂)

_______________________________

6H₂ + 2O₃ => 6H₂O         ΔH₁₂ = -1735.2 Kj       (Net Reaction - not reduced)

________________________________

divide by 2 => target equation (Net Reaction - reduced)

3H₂ + O₃ => 3H₂O            ΔH₁₂ = (-1735.2/2) Kj = -867.2 Kj    

4 0
3 years ago
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