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igomit [66]
3 years ago
9

Someone answer these questions please???

Physics
2 answers:
chubhunter [2.5K]3 years ago
8 0
Yeah sure someone else in answering rn
Fofino [41]3 years ago
4 0

Answer:

a. same

b. less

c. less

Explanation:

you can use the position, time, acceleration equation

xf=xi + vi*t+(at^2)/2

you can say the final distance will greater for X than Y

using acceleration for gravity a=9.81m/s^2

a.  both X and Y will have the same acceleration due to gravity

b. to solve for final speed vf=vi+gt

since the initial velocity is 0 and X will take longer to fall, Y will hit the ground with less speed

c. as mentioned before, X will take longer to fall; therefore Y will have less time of descent.

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A metallic sheet has a large number of slits, 5.0 mm wide and 20 cm apart, and is used as a diffraction grating for microwaves.
san4es73 [151]

To solve this problem it is necessary to apply the concepts related to the principle of superposition and constructive interference, that is to say everything that refers to an overlap of two or more equal frequency waves, which when interfering create a new pattern of waves of greater intensity (amplitude) whose cusp is the antinode.

Mathematically its definition can be given as:

d sin\theta =m\lambda

Where

d = Width of the slit

\theta = Angle between the beam and the source

m = Order (any integer) which represent the number of repetition of the spectrum, at this case 1 (maximum respect the wavelength)

Since the point of the theta angle for which the diffraction becomes maximum will be when it is worth one then we have to:

\lambda = d

\lambda = 20cm = 20*10^{-2}m

Applying the given relation of frequency, speed and wavelength then we will have that the frequency would be:

f = \frac{v}{\lambda}

Here the velocity is equal to the speed of light and the wavelength to the value previously found.

f = \frac{3*10^8}{0.2}

f = 1.5Ghz

Therefore the smallest microwave frequency for which only the central maximum occurs is 1.5Ghz

7 0
3 years ago
An elevator starts from rest with a constant upward acceleration and moves 1 m in the first 1.7 s. A passenger in the elevator i
avanturin [10]

Answer: Tension = 53.6N

Explanation:

Given that

Height h = 1 m

Time t = 1.7 s.

Mass m = 5.1 kg 

From the equation of the motion we can get the acceleration of the elevator:

h = X0+ V0t + at2/2;

Th elevator starts from rest with a constant upward acceleration. Initial velocity Vo = 0, also Xo = 0; thus

a = 2h/t2 = 2 × 1/1.7^2

a = 0.69 m/s2.

Then we can find the tension in the cord by using the formula

T = mg + ma

= 5.1 (9.8 + 0.69)

= 5.1 × 10.5

= 53.6N

7 0
3 years ago
Can someone please help me I don’t understand this
jolli1 [7]
I think it’s a because it the only reasonable answer
4 0
3 years ago
Help me pleaseee, it’s due today: Two people push on a large gate as shown on the view from above in the diagram. If the moment
Sladkaya [172]

Answer:

the angular acceleration of the gate is approximately 1.61  \frac{rad}{s^2}

Explanation:

Recall the formula that connects the net torque with the moment of inertia of a rotating object about its axis of rotation, and the angular acceleration (similar to Newton's second law with net force, mass, and linear acceleration):

\sum \tau_1=I\,\alpha

In our case, both forces contribute to the same direction of torque, so we can add their torques up and get the net torque on the gate:

\tau_{net}=(20*2+30*3.5) \,N\,m=145\,\,N\,m

Now we use this value to obtain the angular acceleration by using the given moment of inertia of the rotating gate:

\sum \tau_1=I\,\alpha\\145\,\,N\.m=(90\,\,kg\,m^2)\,\alpha\\\alpha= \frac{145}{90} \frac{rad}{s^2} = 1.61\, \frac{rad}{s^2}

4 0
3 years ago
When energy is transformed, the amount of usable energy?
cricket20 [7]
Cannot be determined, I need more information.
7 0
3 years ago
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