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Explanation:
Answer:
b. 0.45 meters
Explanation:
Given the following data;
Spring constant, k = 330 N/m
Force = 150 N
To find the extension of the spring;
Mathematically, the force exerted on a spring is given by the formula;
Force = spring constant * extension
Substituting into the formula, we have;
150 = 330 * extension
Extension, e = 150/330
Extension, e = 0.45 meters
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The coefficient of friction between the road and the car's tire is determined as 0.78.
<h3>Acceleration of the car</h3>
The acceleration of the car is calculated as follows;
v² = u² - 2as
0 = u² - 2as
a = u²/2s
where;
- u is the initial velocity = 97 km/h = 26.94 m/s
a = (26.94)²/(2 x 47)
a = 7.72 m/s²
<h3>Coefficient of friction</h3>
μ = a/g
μ = (7.72)/9.8
μ = 0.78
Learn more about coefficient of friction here: brainly.com/question/14121363
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Answer:
The magnetic field in the System is 0.095T
Explanation:
To solve the exercise it is necessary to use the concepts related to Faraday's Law, magnetic flux and ohm's law.
By Faraday's law we know that
Where,
electromotive force
N = Number of loops
B = Magnetic field
A = Area
t= Time
For Ohm's law we now that,
V = IR
Where,
I = Current
R = Resistance
V = Voltage (Same that the electromotive force at this case)
In this system we have that the resistance in series of coil and charge measuring device is given by,
And that the current can be expressed as function of charge and time, then
Equation Faraday's law and Ohm's law we have,
Re-arrange for Magnetic Field B, we have
Our values are given as,
Replacing,
Therefore the magnetic field in the System is 0.095T
