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STatiana [176]
3 years ago
14

When two pool balls collide, what happens to the momentum of each one?

Physics
1 answer:
Schach [20]3 years ago
7 0

Answer:

They slow down.

Explanation:

The collided so the slow down till they stop.

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A change in ________ results in ________.
Triss [41]
I think it's C. I may be wrong, tho
3 0
3 years ago
Part B
dimaraw [331]

At the left side of the reaction

Explanation:

the reaction is spontaneous

8 0
4 years ago
A block of weight 45.7 N is hanging from a rope. The tension from the rope is pulling upward on the block. The block is accelera
viktelen [127]
<h2>Answer:</h2><h2></h2>

52.555 N

<h2>Explanation:</h2>

Let's use Newton's second law of motion here which states that the resultant force (∑F) acting on a body is the product of the mass (m) of the body and the acceleration (a) due to this force. i.e

∑F = m x a            ---------------------(i)

<em>Now, let's get the resultant force;</em>

Two main forces are acting on the rope;

i. the weight (W) of the block acting downwards.

Where;

W = mass of block(m) x gravity(g) = m x g

ii. the tension (T) in the rope acting upwards.

Therefore, the resultant force is the vector sum of these two forces as follows;

∑F = - W + T            [upward motion is taken as positive. hence -W and +T]

<em>Substitute ∑F = - W + T into equation (i) as follows;</em>

- W + T = m x a      ---------------------(ii)

<em>From the question;</em>

* Weight (W) of the block = 45.7N

=> mass (m) of the block = W / g = 45.7 / 10               [Taking g = 10m/s²]

=> m = 4.57 kg

* acceleration (a) = 1.50m/s²

<em>Substitute these values into equation (ii) as follows;</em>

- 45.7 + T = 4.57 x 1.50

- 45.7 + T = 6.855

<em>Solve for T;</em>

T = 6.855 + 45.7

T = 52.555 N

Therefore, the tension in the rope is 52.555 N

   

6 0
4 years ago
Check all that apply. The magnetic force on the current-carrying wire is strongest when the current is parallel to the magnetic
dedylja [7]

Answer:

The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.

The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.

The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.

Explanation:

The magnitude of the magnetic force exerted on a current-carrying wire due to a magnetic field is given by

F=ILB sin \theta (1)

where I is the current, L the length of the wire, B the strength of the magnetic field, \theta the angle between the direction of the field and the direction of the current.

Also, B, I and F in the formula are all perpendicular to each other. (2)

According to eq.(1), we see that the statement:

<em>"The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.</em>"

is correct, because when the current is perpendicular to the magnetic field, \theta=90^{\circ}, sin \theta = 1 and the force is maximum.

Moreover, according to (2), we also see that the statements

<em>"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field. "</em>

<em>"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current. "</em>

because F (the force) is perpendicular to both the magnetic field and the current.

5 0
3 years ago
In a Hydrogen molecule there are a total of four charges, 2 protons in the two nuclei, and 2 electrons. How many unique charge-p
lutik1710 [3]

Answer:

The total number of charge pair without double counting is 6.

Explanation:

Given that,

Number of proton = 2

Number of electron = 2

We need to calculate the total number of charges in Hydrogen atom

Using formula for number of charges

n= p+n

n =2+2

n=4

Number of charge in pair is

r = 2

We need to calculate the total number of possible combination of pairs without double counting

Using formula of combination

N=_{n}C^{r}

Where, n = number of charges

r = number of charges per pair

Put the value into the formula

N=_{4}C^{2}

N=\dfrac{4\times3\times 2}{2(4-2)}

N=\dfrac{4\times3\times 2}{2\times2}

N=6

Hence, The total number of charge pair without double counting is 6.

5 0
3 years ago
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