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stealth61 [152]
3 years ago
15

Where would you expect to have more touch receptors: on the palm of your hand or on the back of your hand? Explain your reasonin

g
Help help help
Physics
1 answer:
anygoal [31]3 years ago
6 0

Answer:

ive answered this

Explanation:

please check your previose question

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Scalar quantities have a size or magnitude only and need no other information to specify them. Thus, 10 cm, 50 sec, 7 litres and 3 kg are all examples of scalar quantities.

Explanation:

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Wheel A has a radius of R and wheel B has a radius of 2R. Wheel A has all the mass at the rim, while wheel B has the mass unifor
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Explanation:

The lesser the moment of inertia, the greater the angular acceleration. Then, the moments of inertia of each wheel are described below:

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I_{B} = \frac{1}{2}\cdot M \cdot (2\cdot R)^{2}

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The wheel A accelerates faster in response to the torque.

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What is the speed of sound at the atmospheric temperature of 30°C?
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The parcel will undergo projectile motion, which means that it will have motion in both the horizontal and vertical direction.


First, we determine how long the parcel will fall using:


s = ut + 1/2 at²


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5.5 = (0)(t) + 1/2 (9.81)(t)²

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(1 point) A projectile is fired from ground level with an initial speed of 600 m/sec and an angle of elevation of 30 degrees. Us
konstantin123 [22]

Answer:

(a) The range of the projectile is 31,813.18 m

(b) The maximum height of the projectile is 4,591.84 m

(c) The speed with which the projectile hits the ground is 670.82 m/s.

Explanation:

Given;

initial speed of the projectile, u = 600 m/s

angle of projection, θ = 30⁰

acceleration due to gravity, g = 9.8 m/s²

(a) The range of the projectile in meters;

R = \frac{u^2sin \ 2\theta}{g} \\\\R = \frac{600^2 sin(2\times 30^0)}{9.8} \\\\R = \frac{600^2 sin (60^0)}{9.8} \\\\R = 31,813.18 \ m

(b) The maximum height of the projectile in meters;

H = \frac{u^2 sin^2\theta}{2g} \\\\H = \frac{600^2 (sin \ 30)^2}{2\times 9.8} \\\\H = \frac{600^2 (0.5)^2}{19.6} \\\\H = 4,591.84 \ m

(c) The speed with which the projectile hits the ground is;

v^2 = u^2 + 2gh\\\\v^2 = 600^2 + (2 \times 9.8)(4,591.84)\\\\v^2 = 360,000 + 90,000.064\\\\v = \sqrt{450,000.064} \\\\v = 670.82 \ m/s

5 0
3 years ago
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