Question

A sample of oxygen occupies 1.00 L. If the temperature remains constant, and the pressure on the oxygen is decreased to one third the original pressure, what is the new volume

Answer 1

Answer:

3.00 L

Explanation:

P₁V₁ = P₂V₂

V₁ = 1.00 L

P₁ = (x) atm

P₂ = $\frac{1}{3}$ · (P₁) = $\frac{x}{3}$

V₂ = unknown

(x atm)(1.00 L) = ( $\frac{x}{3}$ atm)(V₂)

divide both sides by ( $\frac{x}{3}$ atm)

( 1.00x )( $\frac{3}{x}$ ) = V₂

x cancels out

(1.00)(3) = V₂

V₂ = 3.00 L