Answer:
The resistance of the aluminium wire is 0.541 ohms
Explanation:
Given:
Cross sectional area of the aluminum wire, A = 4.9 x 10-4 m2
Length of the wire, L = 10 km = 10,000 m
Resistance of the wire = (pL) / A
Where:
p is resistivity of aluminium wire = 2.65 x 10^-8 ohm-m
L is length of the wire
A is cross sectional area of the wire
Substitute these values and solve for resistance of the wire.
Resistance = (2.65 x 10^-8 x 10,000) / (4.9 x 10^-4)
Resistance = 0.541 ohms
Therefore, the resistance of the aluminium wire is 0.541 ohms
There mass is a different size (weight)
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Answer:
Private jet is 200 mph
Commercial jet is 225 mph
Explanation:
Let the speed of private jet be x mph therefore the speed of commercial jet will be 2x-175 mph
The distance is the same
Speed is distance per unit time hence distance is product of speed and time
Distance by private jet is 9x
Distance by commercial jet is 8(2x-175)
Since the distance is the same
9x=8(2x-175)
9x=16x-1400
7x=1400
X=200
Then 2x-175= 400-175=225
Speed of private jet is 200 mph while commercial jet is 225 mph
Answer:
B. energy
Explanation:
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