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3 years ago

Which inequality is true when the value of x is-3?

Mathematics

1 answer:

kari74 [83]3 years ago

8 0

Answer:

pooop VVVFind the area the grass seed needs to cover.Find the area the grass seed needs to cover.Find the area the grass seed needs to cover.

Step-by-step explanation:

12 x 2 + 90.

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Please help me on #13

qwelly [4]

Answer:

2.765 Miles is how much he ran

8 0

4 years ago

33. Suppose you were on a planet where the

tatyana61 [14]

Answer:

a) 3.675 m

b) 3.67m

Explanation:

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

4 years ago

A flying saucer crashes in a Nebraska cornfield. The FBI investigates the wreckage and finds an engineering manual containing an

anyanavicka [17]

Answer:

6 fingers

Step-by-step explanation:

Let X = the base of the numbers above

If X > 0

Then we have:

325 = 3 * X² + 2 * X¹ + 5 * X°

325 = 3X² + 2X + 5

42 = 4*X¹ + 2*X°

42 = 4X+ 2

And

411 = 4*X²+ 1*X¹ 1*X°

42 = 4X² + X + 1

Since 325 + 42= 11 then

3X² + 2X + 5 + 4X+ 2 = 4X² + X + 1 ------ Collect Like Terms

3X² - 4X² + 2X + 4X - X + 5 + 2 - 1 = 0

-X² + 5X + 6 = 0 ------- Multiply both sides by -1

X² - 5X - 6 = 0 ------- Factorise the Equation

X² - 6X + X - 6 = 0

X(X - 6) + 1( X - 6) = 0

(X + 1)(X - 6) = 0

X + 1 = 0 or X - 6 = 0

X = -1 or X = 6

But X>0

So, X =-1 is invalid

X = 6

The expected number of fingers of the Martian is 6

6 0

4 years ago

Suppose the length of the base b of a rectangle is increased by 20 percent and the length of the altitude h is increased by 40 p

jek_recluse [69]

9514 1404 393

Answer:

(a) 1.2b

(b) 1.4h

(d) 68%

Step-by-step explanation:

(a) If 20% of b is added to b, you have ...

b + 0.20b = 1.2b

(b) Similarly, if 40% of h is added to h, you have ...

1.4h

A = (1.2b)(1.4h)

A = 1.68bh

(d) The original rectangle area is A = bh, so the percentage change can be computed as ...

(A'/A -1)×100% = ((1.68bh)/(bh) -1)×100% = (1.68 -1)×100% = 68%

The given increases in base and height increase the area by 68%.

5 0

3 years ago

Can someone please help me

Irina18 [472]

Answer:

-11, -5, -23, 7

Step-by-step explanation:

plug in the h value into equation

-2(2)-7

-11

-2(-1)-7

-5

-2(8)-7

-23

-2(-7)-7

5 0

4 years ago