Explanation:
The given data is as follows.
E.m.f = 12 V, Voltage = 10 V, Resistance = 2 ohm
Hence, calculate the current as follows.
I = 
Putting the given values into the above formula as follows.
I = 
= 
= 1 A
Atomic weight of copper is 63.54 g/mol. Therefore, equivalent weight of copper is
.
That is, 
= 
Hence, electrochemical equivalent of copper is as follows.
Z = (\frac{E}{96500}) g/C
= (\frac{63.54 g/mol}{2 \times 96500}) g/C
=
g/C
Therefore, charge delivered from the battery in half-hour is calculated as follows.
It = Q
=
= 1800 C
So, copper deposited at the cathode in half-an-hour is as follows.
M = ZQ
= 
= 0.5927 g
Thus, we can conclude that 0.5927 g of copper is deposited at the cathode in half an hour.
Answer:
any litter on the ground can be swept up into the runoff. dirty ground water also commonly affects runoff since there are so many chemicals in the ground. farmers especially need to be cautious because teir fertilizers can leak into the ground.
Phosphorus trichloride is the precursor to organophosphorus compounds that contain one or more P(III) atoms, most notably phosphites and phosphonates. ... PCl3 reacts vigorously with water to form phosphorous acid, H3PO3 and HCl: PCl3 + 3 H2O → H3PO3 + 3 HCl.
Answer:
94.325 g
Explanation:
We'll begin by converting 350 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
350 mL = 350 mL × 1 L /1000 mL
350 mL = 0.35 L
Next, we shall determine the number of mole of KC₂H₃O₂ in the solution. This can be obtained as follow:
Volume = 0.35 L
Molarity of KC₂H₃O₂ = 2.75 M
Mole of KC₂H₃O₂ =?
Molarity = mole /Volume
2.75 = Mole of KC₂H₃O₂ / 0.35
Cross multiply
Mole of KC₂H₃O₂ = 2.75 × 0.35
Mole of KC₂H₃O₂ = 0.9625 mole
Finally, we shall determine the mass of KC₂H₃O₂ needed to prepare the solution. This can be obtained as illustrated below:
Mole of KC₂H₃O₂ = 0.9625 mole
Molar mass of KC₂H₃O₂ = 39 + (12×2) +(3×1) + (16×2)
= 39 + 24 + 3 + 32
= 98 g/mol
Mass of KC₂H₃O₂ =?
Mass = mole × molar mass
Mass of KC₂H₃O₂ = 0.9625 × 98
Mass of KC₂H₃O₂ = 94.325 g
Thus, the mass of KC₂H₃O₂ needed to prepare the solution is 94.325 g