Percent yield or yield is mathematically defined as:
Yield = Actual amount / Theoretical amount
So to solve the yield, let us first calculate the
theoretical amount of POCl3 produced. The balanced chemical reaction for this
is:
6 PCl5 + P4O10 ---> 10 POCl3
Since P4O10 is stated to be supplied in large amount, then
PCl5 becomes the limiting reactant.
So we calculate for POCl3 based on PCl5. To do this let us
convert the amount into moles: (molar mass PCl5 = 208.24 g/mol)
n PCl5 = 42.66
grams / (208.24 g/mol)
n PCl5 = 0.205 mol
Now based on the
stoichiometric ratio of the reaction:
<span>n POCl3 = 0.205 mol (10
POCl3 / 6 PCl5)
n POCl3 = 0.3414 mol POCl3</span>
Converting to mass (molar
mass POCl3 = 153.33 g/mol)
m POCl3 = 0.3414 mol (153.33 g/mol)
m POCl3 = 52.35 g
Calculating for yield:
Yield = 47.22 g/ 52.35 g
Yield = 0.902
<span>%Yield = 90.2 % (ANSWER)</span>
Answer:
The two samples have identical properties because they are the samples of the same element. Intensive properties are properties of matter that do not change depending on the amount of matter. Luster, reactivity, and ductility are all intensive properties. That is why the two samples can be different sizes or shapes, but have identical properties.
Answer:
3.1°C
Explanation:
Using freezing point depression expression:
ΔT = Kf×m×i
<em>Where ΔT is change in freezing point, Kf is freezing point depression constant (5.12°c×m⁻¹), m is molality of the solution and i is Van't Hoff factor constant (1 For I₂ because doesn't dissociate in benzene).</em>
Molality of 9.04g I₂ (Molar mass: 253.8g/mol) in 75.5g of benzene (0.0755kg) is:
9.04g ₓ (1mol / 253.8g) = 0.0356mol I₂ / 0.0755kg = 0.472m
Replacing in freezing point depression formula:
ΔT = 5.12°cm⁻¹×0.472m×1
ΔT = 2.4°C
As freezing point of benzene is 5.5°C, the new freezing point of the solution is:
5.5°C - 2.4°C =
<h3>3.1°C</h3>
<em />
Answer:
a) Molarity = 0.199M
b) 21.6L of solution
c) 0.199 moles of sucrose in 1L
Explanation:
a) Molarity is the ratio of moles of solute (sucrose) in volume of solution (3.30L):
<em>Moles sucrose -Molar mass: 342,3g/mol-:</em>
225.0g * (1mol / 342,2965g) = 0.6573 moles
Molarity = 0.6573 moles / 3.30L
<h3>Molarity = 0.199M</h3><h3 />
b) 0.199M means 0.199 moles in 1L. 4.30 moles are in:
4.30 mol * (1L / 0.199mol) = 21.6L of solution
c) By definition, there are 0.199 moles of sucrose in 1L. This is the meaning of 0.199M
