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Elis [28]
3 years ago
9

A plant is removing a trace of Cl2 from a waste gas stream by passing it over a solid granular absorbed in a tubular packed bed.

At present, 63.2 % removal is being accomplished, but it is believed that greater removal could be achieved if the flow rate were increased by a factor of 4, the particle diameter were decreased by a factor of 3, and the packed tube length increased by 50%. What percentage of chlorine would be removed under the proposed scheme? ( The chlorine transferring to the absorbent is removed completely by a virtually instantaneous chemical reaction.)

Chemistry
1 answer:
kow [346]3 years ago
5 0

Answer:

Percentage of Chlorine removed = 98%

Explanation:

Attached

 

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The formation of nitric acid from nitrogen, hydrogen, and oxygen can be written as,

     N₂ + H₂ + 3O₂ --> 2HNO₃

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Since all the reactants are in their elemental forms, the simplified equation would be,

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3 years ago
Bob measured out 1.60 grams of sodium. He calculates that 1.60 g of
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Answer:

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Explanation:

Step 1: Given data

Bob measured out 1.60 g of Na. He forms NaCl according to the following equation.

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According to this equation, he calculates that 1.60 g of sodium should produce 4.07 g of NaCl, which is the theoretical yield. However, he carries out the experiment and only makes 3.45 g of NaCl, which is the real yield.

Step 2: Calculate the percent yield.

We will use the following expression.

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%yield = 3.45 g / 4.07 g × 100% = 84.8%

6 0
3 years ago
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