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Elis [28]
3 years ago
9

A plant is removing a trace of Cl2 from a waste gas stream by passing it over a solid granular absorbed in a tubular packed bed.

At present, 63.2 % removal is being accomplished, but it is believed that greater removal could be achieved if the flow rate were increased by a factor of 4, the particle diameter were decreased by a factor of 3, and the packed tube length increased by 50%. What percentage of chlorine would be removed under the proposed scheme? ( The chlorine transferring to the absorbent is removed completely by a virtually instantaneous chemical reaction.)

Chemistry
1 answer:
kow [346]3 years ago
5 0

Answer:

Percentage of Chlorine removed = 98%

Explanation:

Attached

 

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Kc is 1.67 x 10^20 at 25 °C for the formation of iron(III) oxalate complex ion:
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Answer:

n_{C_2O_4^{2-}}=1.59mol C_2O_4^{2-}

Explanation:

Hello there!

In this case, according to the given information and chemical equation, it turns out possible for us to calculate the moles of C2O4^2- by firstly setting up the equilibrium expression:

Kc=\frac{[[Fe(C_2O_4)_3]^{3-}]}{[Fe^{3+}][C_2O_4^{2-}]^3}

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n_{C_2O_4^{2-}}=0.53molFe^{3+}*\frac{3molC_2O_4^{2-}}{1molFe^{3+}}=1.59mol C_2O_4^{2-}

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A sample of neon occupies a volume of 461 mL at 1 atm and 273 K. What will be the volume of the neon when the pressure is reduce
Softa [21]

Answer:

0.501 L

Explanation:

To solve this problem we will use Boyle,s Law. According to this law "The volume of given amount of gas is inversely proportional to applied pressure at constant temperature".

                           V∝ 1/P

                           V= K/P

                            VP=K

Here the K is proportionality constant.

so,

             P1V1 = P2V2

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Given data:

P1= 1 atm

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P2= 0.92 atm

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To solve this problem we have to convert the mL into L first.

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461/1000= 0.461 L

Now we will put the values in the equation,

P1V1 = P2V2

V2= P1V1/ P2

V2= 1 atm × 0.461 L / 0.92 atm

V2= 0.501 L

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