Answer:
15.04 mL
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 21 L
V₂ = ?
P₁ = 9 atm
P₂ = 15 atm
T₁ = 253 K
T₂ = 302 K
Using above equation as:
Solving for V₂ , we get:
<u>V₂ = 15.04 mL</u>
_NH3 + _ 02 →_NO + _ H2O Balanced
1 answer:
You might be interested in
The standard potential for the given galvanic cell is 0.477 V
<h3>What is electrode potential?</h3>The electrode potential is the electromotive force of a galvanic cell built using a standard reference electrode and another electrode whose potential is to be found.
There are two types of electrode potential
Oxidation potential - The potential associated with oxidation reaction is known as oxidation potential
Reduction potential - The potential associated with reduction reaction is known as reduction potential
At the anode, oxidation occurs
At the cathode, reduction occurs
= 0.337 - (-0.140)
= 0.477 V
Thus, The standard potential for the given galvanic cell is 0.477 V
Learn more about electrode potential:
#SPJ4
Disclaimer: The question was given incomplete on the portal. Here is the complete question
Question: What is the standard potential, E∘cell, for this galvanic cell? Use the given standard reduction potentials in your calculation as appropriate.
, E°red=−0.140 V
, E°red=+0.337 V