Answer:
Nitrogen tribromide is a chemical compound with the formula NBr3. It is extremely explosive in its pure form, even at −100 °C, and was not isolated until 1975.
Substances that cannot be separated and found on a periodic table are elements.
Answer:
1. The balanced thermochemical equation for the reaction is;
2C4H10 (g) + 13O2 (g) -----------> 8CO2 (g) + 10H20 (g)
2. Heat when 200g of butane is burned is 9925.65 kJ of heat
Explanation:
2 moles of butane reacts with oxygen in excess to produce carbon iv oxide and water
If 1 mole releases 2877kJ of heat
2 moles will release (2 * 2877kJ) of heat
= 5754 kJ of heat.
The mass of butane used is 200g and converting it to moles we have;
n = mass / molar mass
molar mass of butane = (12 *4 + 1 *10) = 58 g/mol
So therefore n = 200 g/ 58 g/mol
n= 3.45 moles of butane.
If 1 mole of buatne releases 2877 kJ of heat
3.45 moles will release ( 3.45 * 2877 kJ ) of heat
= 9925.65 kJ of heat
9925.65 kJ of heat is released when 200 g of butane is burned.
Answer:
minus 273.15 degrees on the Celsius scale
Explanation:
minus 459.67 degrees Fahrenheit.
Formula:Deduct 32, then multiply by 5, then divide by 9
Answer:
Saturated = The solution cannot dissolve any more solute at a given temperature
2) Unsaturated = solution can dissolve more solute at a given temperature.
3) Supersaturated = Solution which has more solute than its saturated solution
Explanation:
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