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3 years ago

Write the chemical equation of in elements

Chemistry

1 answer:

Scilla [17]3 years ago

8 0

Answer : The balanced chemical reaction will be:

$CuO+H_2SO_4\rightarrow CuSO_4+H_2O$

Explanation :

As per question when copper(II) oxide react with sulfuric acid then it gives copper(II) sulfate and water.

This reaction is known as double displacement reaction in which cation of two reactants exchange their places to give two different products.

The balanced chemical reaction will be:

$CuO+H_2SO_4\rightarrow CuSO_4+H_2O$

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Structure of 4-ethylheptene

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Answer:

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Chemical Safety Laboratory Chemical Safety Summary (LCSS) Datasheet

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Explanation:

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3 years ago

How many moles in 5 grams of gold

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3 years ago

Read 2 more answers

Carbon monoxide (CO) reacts with hydrogen (H2) to form methane (CH4) and water (H2O).

Artemon [7]

Answer:

5.9x10^-2 M

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Concentration of CO, [CO] = 0.30 M

Concentration of H2, [H2] = 0.10 M

Concentration of H2O, [H2O] = 0.020 M

Equilibrium constant, K = 3.90

Concentration of CH4, [CH4] =..?

Step 2:

The balanced equation for the reaction. This is given below:

CO(g) + 3H2(g) <=> CH4(g) + H2O(g)

Step 3:

Determination of the concentration of CH4.

The expression for equilibrium constant of the above equation is given below:

K = [CH4] [H2O] / [CO] [H2]^3

3.9 = [CH4] x 0.02/ 0.3 x (0.1)^3

Cross multiply to express in linear form

[CH4] x 0.02= 3.9 x 0.3 x (0.1)^3

Divide both side by 0.02

[CH4] = 3.9 x 0.3 x (0.1)^3 /0.02

[CH4] = 5.9x10^-2 M

Therefore, the equilibrium concentration of CH4 is 5.9x10^-2 M

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Answer:

Its a simple SERIES circuit

Explanation:

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3 years ago