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Gala2k [10]
3 years ago
14

A given volume of gas at a temperature of 100 K has a

Chemistry
1 answer:
stepan [7]3 years ago
6 0

Answer:

200K

Explanation:

Pressure is directly proportional to temperature.

100=225

x=450

(100*450)/225=x

x=45000/225

x=200

You might be interested in
What is reacitivty series, and how you can access reactivity of metals...
lubasha [3.4K]

In Chemistry, a reactivity series of metals , also known as the activity series refers to the arrangement of metals in the descending order based upon their reactivity .

<u>Salient Features</u> :-

  • The metal at the top of the reactivity series are powerful reducing agents since they are easily oxidized.
  • The reducing ability of metals grows weaker while traversing down the series.
  • The electro-positivity of metals also reduces while moving down the reactivity series.
  • Metals that are placed higher on the reactivity series have the ability to displace metals that are placed lower in the series.

<u>The metal reactivity series is given below</u> :-

To access the reactivity of metal , from the given reactivity series identify any of the metal and locate the reactivity based upon the choice of reactivity. The metal at the top (Potassium) is most reactive and the metal at the bottom (Platinum) is the least reactive.

To learn more about metal reactivity series visit -

brainly.com/question/16072297

8 0
2 years ago
A hamburger containing 335.4 kcal of energy was combusted in a bomb calorimeter with an unknown heat capacity. The temperature o
Zielflug [23.3K]

Answer:

Cv_{calorimeter}=18.4kcal/K

Explanation:

Hello!

In this case, since the combustion of the hamburger released 335.4 kcal of energy and that energy is received by the calorimeter, we can write:

Q_{hamburguer}=-Q_{calorimeter}

And the heat of the calorimeter is written in terms of the temperature change and the calorimeter constant:

Q_{hamburguer}=-Cv_{calorimeter}\Delta T

Thus, given the released heat by the hamburger due to its combustion and the temperature change, Cv for the calorimeter turns out:

Cv_{calorimeter}=\frac{-Q_{hamburguer}}{\Delta T} =\frac{-(-335.4kcal)}{18.2K}\\\\Cv_{calorimeter}=18.4kcal/K

Best regards!

4 0
3 years ago
When hydrogen sulfide gas is bubbled into a solution of sodium hydroxide, the reaction forms sodium sulfide and water. How many
Mumz [18]

Answer:

1.61 g Na₂S

Explanation:

To find the mass of sodium sulfide (Na₂S) generated from hydrogen sulfide (H₂S) and sodium hydroxide (NaOH), you need to (1) construct the balanced chemical equation, then (2) calculate the molar masses of each molecule involved, then (3) convert grams of each reagent to grams of the product (via the molar masses and mole-to-mole ratio from equation coefficients), and then (4) determine the limiting reagent and final answer. It is important to arrange the conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).

(Step 1)

The unbalanced equation:

H₂S + NaOH ---> Na₂S + H₂O

Reactants: 3 hydrogen, 1 sulfur, 1 sodium, 1 oxygen

Products: 2 hydrogen, 1 sulfur, 2 sodium, 1 oxygen

The balanced equation:

H₂S + 2 NaOH ---> Na₂S + 2 H₂O

Reactants: 4 hydrogen, 1 sulfur, 2 sodium 2 oxygen

Products: 4 hydrogen, 1 sulfur, 2 sodium, 4 oxygen

(Step 2)

Molar Mass (H₂S): 2(1.008 g/mol) + 32.065 g/mol

<u>Molar Mass (H₂S)</u>: 34.081 g/mol

Molar Mass (NaOH): 22.990 g/mol + 15.998 g/mol + 1.008 g/mol

<u>Molar Mass (NaOH)</u>: 39.998 g/mol

Molar Mass (Na₂S): 2(22.990 g/mol) + 32.065 g/mol

<u>Molar Mass (Na₂S)</u>: 78.045 g/mol

(Step 3)

1.50 g H₂S          1 mole            1 mole Na₂S          78.045 g
-----------------  x  ----------------  x  --------------------  x  -----------------  =
                           34.081 g          1 mole H₂S            1 mole

=  3.43 g Na₂S

1.65 g NaOH           1 mole              1 mole Na₂S          78.045 g
--------------------  x  ----------------  x  -----------------------  x  ----------------  =
                              39.998 g        2 moles NaOH          1 mole

=  1.61 g Na₂S

(Step 4)

Because NaOH generates less product, it will run out before all of the H₂S is used. This makes NaOH the limiting reagent and the final answer 1.61 grams Na₂S.

5 0
2 years ago
What is pH?
sergij07 [2.7K]
PH = -log[H+]
That is, pH is the negative logarithm of the hydrogen ion concentration.

pOH = -log[OH-]
pOH is the negative logarithm of the hydroxide ion concentration.

The correct answer to your question is a. The negative logarithm of the hydrogen ion concentration.
5 0
3 years ago
A sample of hydrogen gas has an initial pressure of 2.86 atm and an initial volume of 8472 mL If the volume of the
Oliga [24]
<h3>Answer:</h3>

Gas law : Boyle's law

New pressure: 66.24 atm

<h3>Explanation:</h3>

Concept tested: Gas laws (Boyle's law)

<u>We are given,</u>

  • Initial pressure, P₁ = 2.86 atm
  • Initial volume, V₁ = 8472 mL
  • New volume, V₂ IS 365.8 mL

We need to determine the new pressure, P₂

  • According to Boyle's law , the volume of a fixed mass of a gas and the pressure are inversely proportional at constant temperature.
  • That is, P\alpha \frac{1}{V}
  • This means , PV = k (constant)
  • Therefore; P₁V₁ = P₂V₂
  • Rearranging the formula, we can get the new pressure, P₂

P₂ = P₁V₁ ÷ V₂

   = (2.86 atm × 8472 mL) ÷ 365.8 mL

   = 66.24 atm

Therefore, the new pressure is 66.24 atm

5 0
3 years ago
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