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3 years ago

Write the slope-intercept form of the equation of each line given the slope and y-intercept.

Mathematics

1 answer:

Readme [11.4K]3 years ago

3 0

Answer:

y = -3x-2

Step-by-step explanation:

Slope intercept form is: y = mx+b

m = slope

b = y - intercept

Substitute: y = -3x - 2

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Whats the area of the triangle? (10,8,12.8)

statuscvo [17]

Answer:

LXBXH

AREA=10X8X12.8

AREA=1024

4 0

2 years ago

The length of a rectangle is the sum of the width and 4. The area of the rectangle is 32

Sauron [17]

Answer:

The width of rectangle w = 4 units

Step-by-step explanation:

We are given:

Width of rectangle = w

Length of rectangle = w+ 4

Area of rectangle = 32 units

We need to find width of the rectangle

The formula used is: $Area\:of\:rectangle=Length\times Width$

Putting values and finding width of rectangle

$Area\:of\:rectangle=Length\times Width\\32=(w+4)\times w\\32=w^2+4w\\w^2+4w-32=0$

We need to solve this quadratic equation to find width (w)

We will use factorisation and break the middle term.

$w^2+4w-32=0\\w^2+8w-4w-32=0\\w(w+8)-4(w+8)=0\\(w-4)(w+8)=0\\w-4=0\:or\:w+8=0\\w=4\:or\:w=-8$

Since width of rectangle can't be negative, so rejecting w=-8

Therefore, the width of rectangle w = 4 units

4 0

3 years ago

Together, teammates Pedro and Ricky got 2676 base hits last season. Pedro had 276 more hits than Ricky. How many hits did each

Alborosie

Let's use the variable r to represent ricky's base hits:
Ricky is r
Pedro is r + 276
So:
r + r + 276 = 2676
2r = 2400
r= 1200
Ricky hit 1200 base hits, and Pedro hit 1476 base hits.

4 0

2 years ago

From the side view, a gymnastics mat forms a right triangle with other angles measuring 60° and 30°. The gymnastics mat extends

valkas [14]

Answer: The mat is 4.33 ft high off the ground.

Step-by-step explanation:

Since we have given that

Angle of elevation with the first triangle = 30°

Angle of elevation with the second triangle = 60°

Length at which gymnastics mat extends across the floor = 5 feet

so, As shown in the figure:

We need to find the height of the mat off the ground.

If CD = 5 ft,

Let, AB = y, DC = x.

In Δ ABC,

$\tan 60^\circ=\frac{AB}{BC}\\\\\frac{\sqrt{3}}{2}=\frac{y}{x}\\\\x=\frac{y}{\sqrt{3}}$

Similarly, in Δ ACD,

$\tan 30^\circ=\frac{AB}{BD}\\\\\frac{1}{\sqrt{3}}=\frac{y}{x+5}\\\\\frac{1}{\sqrt{3}}=\frac{y}{\frac{y}{\sqrt{3}}+5}\\\\\frac{1}{\sqrt{3}}=\frac{y\sqrt{3}}{y+5\sqrt{3}}\\\\3y=y+5\sqrt{3}\\\\2y=5\sqrt{3}\\\\y=\frac{5\sqrt{3}}{2}\\\\y=4.33\ ft$

Hence, the mat is 4.33 ft high off the ground.

5 0

3 years ago

Read 2 more answers

Find the total amount and amount of interest paid in the following compound interest problems. $900 at 6%, for 10 years.

Naddik [55]

Your monthly payment would be $9.99 that is your answer to your question.

I hope this is what you are looking for have i nice week

8 0

3 years ago