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nasty-shy [4]
3 years ago
15

An initially motionless test car is accelerated uniformly to 120 km/h in 8.28 s before striking a simulated deer. The car is in

contact with the faux fawn for 0.815 s, after which the car is measured to be traveling at 71.0 km/h. What is the magnitude of the acceleration of the car before the collision
Physics
1 answer:
Anestetic [448]3 years ago
4 0

Answer:

The value is   a =  4.0 \ m/s^2

Explanation:

From the question we are told that  

  The velocity  is  a =  120 \  km/h =  [tex]\frac{120 *  1000}{3600} =  33.3 \  m/s[/tex]

  The time taken is t  =  8.28 \  s

    The  time taken for contact is  t_c  =  0.815 \  s

     The  velocity of the of the car after contact is v_c =  71.0 \  km/h = [tex]\frac{71 *1000}{3600} =  19.7 2 \  m/s[/tex]

From the equation of kinematics we have that  

       v =  u  + at

Here   u =  0 \ m/s  since the car is initially motionless

=>    33.3 =  0  + a *  8.28

=>    a =  4.0 \ m/s^2

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f.The period is independent of the suspended mass.

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From the formula, we see that:

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Note: statement "e.The period is proportional to the length of the wire" is also wrong, because the period is NOT proportional to the length of the wire, but it is proportional to the square root of it.

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What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?
konstantin123 [22]

Answer:

I=2.71\times 10^{-5}\ A

Explanation:

A 6.0-cm-diameter parallel-plate capacitor has a 0.46 mm gap.  

What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?

Let given is,

The diameter of a parallel plate capacitor is 6 cm or 0.06 m

Separation between plates, d = 0.046 mm

The potential difference across the capacitor is increasing at 500,000 V/s

We need to find the displacement current in the capacitor. Capacitance for parallel plate capacitor is given by :

C=\dfrac{A\epsilon_o}{d}\\\\C=\dfrac{\pi r^2\epsilon_o}{d}, r is radius

Let I is the displacement current. It is given by :

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So, the value of displacement current is 2.71\times 10^{-5}\ A.

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