1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dominik [7]
3 years ago
12

In two or more complete sentences, explain how you can prove that the number of degrees that the Moon rotates around the Earth e

ach day is approximately 12.2⁰. Write your response in the essay box below.
Physics
2 answers:
Julli [10]3 years ago
7 0

Answer:

According to this solution, the Moon has two main motions, revolution and rotation. The Moon moves around the world in the movement called a revolution, in which an average of around 13.2 ° per day, or 92 degrees per week, or once in 27.3 days, is the annual movement of the moon around the Earth.

PolarNik [594]3 years ago
3 0

Answer:

Follows are the explanation to this question:

Explanation:

In this solution, it is defined that there are two principal motions for the moon, which are its revolution as well as rotation. In such a movement called revolution, its Moon is relocating around the Earth, in which the approximate movement of the moon from around earth has an average movement of about 13.2° per day, or 92 degrees every week, that's once in 27.3 days.

You might be interested in
A projectile launcher has a mass of 3 kg. It fires a projectile of mass 0.08 kg horizontally at a speed of 300 m/s. a. What is t
alexdok [17]

Answer:

0

Explanation:

It’s before the projectile was fired, so nothing has happened yet.

6 0
2 years ago
Given that the atomic weight of hydrogen is approximately 1 gram per mole, use the method above to estimate the average molecula
denpristay [2]

Answer:

2

Explanation:

6 0
3 years ago
In a Hydrogen atom an electron rotates around a stationary proton in a circular orbit with an approximate radius of r =0.053nm.
leonid [27]

Answer:

(a): F_e = 8.202\times 10^{-8}\ \rm N.

(b): F_g = 3.6125\times 10^{-47}\ \rm N.

(c): \dfrac{F_e}{F_g}=2.27\times 10^{39}.

Explanation:

Given that an electron revolves around the hydrogen atom in a circular orbit of radius r = 0.053 nm = 0.053\times 10^{-9} m.

Part (a):

According to Coulomb's law, the magnitude of the electrostatic force of interaction between two charged particles of charges q_1 and q_2 respectively is given by

F_e = \dfrac{k|q_1||q_2|}{r^2}

where,

  • k = Coulomb's constant = 9\times 10^9\ \rm Nm^2/C^2.
  • r = distance of separation between the charges.

For the given system,

The Hydrogen atom consists of a single proton, therefore, the charge on the Hydrogen atom, q_1 = +1.6\times 10^{-19}\ C.

The charge on the electron, q_2 = -1.6\times 10^{-19}\ C.

These two are separated by the distance, r = 0.053\times 10^{-9}\ m.

Thus, the magnitude of the electrostatic force of attraction between the electron and the proton is given by

F_e = \dfrac{(9\times 10^9)\times |+1.6\times 10^{-19}|\times |-1.6\times 10^{-19}|}{(0.053\times 10^{-9})^2}=8.202\times 10^{-8}\ \rm N.

Part (b):

The gravitational force of attraction between two objects of masses m_1 and m_1 respectively is given by

F_g = \dfrac{Gm_1m_2}{r^2}.

where,

  • G = Universal Gravitational constant = 6.67\times 10^{-11}\ \rm Nm^2/kg^2.
  • r = distance of separation between the masses.

For the given system,

The mass of proton, m_1 = 1.67\times 10^{-27}\ kg.

The mass of the electron, m_2 = 9.11\times 10^{-31}\ kg.

Distance between the two, r = 0.053\times 10^{-9}\ m.

Thus, the magnitude of the gravitational force of attraction between the electron and the proton is given by

F_g = \dfrac{(6.67\times 10^{-11})\times (1.67\times 10^{-27})\times (9.11\times 10^{-31})}{(0.053\times 10^{-9})^2}=3.6125\times 10^{-47}\ \rm N.

The ratio \dfrac{F_e}{F_g}:

\dfrac{F_e}{F_g}=\dfrac{8.202\times 10^{-8}}{3.6125\times 10^{-47}}=2.27\times 10^{39}.

6 0
3 years ago
Jim is driving a 2268-kg pickup truck at 22 m/s and releases his foot from the accelerator pedal. The car eventually stops due t
shutvik [7]

Answer:

610 meters.

Explanation:

Because Jim released the accelerator, the truck started to slow down, so the friction force will eventually stop the truck.

the kinetic energy of the truck just after Jim released the pedal is:

E_k=\frac{1}{2}*m*v^2\\E_k=\frac{1}{2}*2268*(22)^2=548856J

The work done by the friction force is given by:

W_f=F_s*d\\\\d=\frac{548856J}{900N}\\\\d=610m

6 0
3 years ago
When the starter motor on a car is engaged, there is a 310 A current in the wires between the battery and the motor. Suppose the
Blababa [14]

Answer:

Diameter will be 351.42 mm

Explanation:

We have given current flowing in the copper wire i = 310 A

Voltage drop across the wire V = 0.55 volt

We know that resistance is given by R=\frac{V}{i}=\frac{0.55}{310}=0.00177\Omega

Length of the copper wire l = 1 m

Resisitivity of the copper wire \rho =1.72\times 10^{-8}\Omega m

We know that resistance R=\frac{\rho l}{A}

0.00177=\frac{1.72\times 10^{-8}\times  1}{A}

A=969.4545\times 10^{-8}m^2

As area A=\pi r^2

3.14\times r^2=969.4545\times 10^{-8}

r=17.57\times 10^{-4}m

So diameter d=17.57\times 10^{-4}\times 2=35.142\times \times 10^{-4}m = 351.42 mm

3 0
3 years ago
Other questions:
  • The magnetic field at the center of a wire loop of radius , which carries current , is 1 mT in the direction (arrows along the w
    9·1 answer
  • A bike rider does work to get to the top of a mountain. How could you use the law of conservation of energy to describe his trip
    14·1 answer
  • When a liquid has vapor pressure equal to atmospheric pressure, it?
    12·2 answers
  • Two circular plates, each with a radius of 8.22 cm,8.22 cm, have equal and opposite charges of magnitude 3.952 μC.3.952 μC. Calc
    14·1 answer
  • Light of wavelength 600 nm illuminates a diffraction grating. The second order maximum is at an angle of 65 degrees. a) List you
    6·1 answer
  • Check cashing businesses do not require that an individual be an account holder; they will cash any valid check. True False
    6·2 answers
  • What happens when the data in an experiment does not support the hypothesis?
    6·1 answer
  • Imagine a block that is 10 cm x 10 cm x 10 cm. If you cut the block in half, what then would be the dimensions of 1/2 of the blo
    10·1 answer
  • Suppose a particle is accelerated through space (no gravity) by a 10 N force. Suddenly the particle encounters a second force of
    6·1 answer
  • The spring in the toy is compressed 0.070 meter by using a downward force of 12.0 newtons. Calculate the spring constant, in N/m
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!