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3 years ago

A group of students designed the string drip system to water plants without irrigation, as shown in the image. They placed a jug

Physics

2 answers:

Aleks04 [339]3 years ago

8 0

Answer:

D add more string and water

kati45 [8]3 years ago

4 0

Add more water to the jig

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If you dropped a rock and it fell 4.9 m in 1 s , how far would it fall in 3 s

GalinKa [24]

The formula relevant for this is:

h = v0t + 0.5 gt^2

since the rock was dropped, therefore:

h = 0.5 gt^2

we can see that:

h / t^2 = 0.5 g = constant

therefore:

4.9 m / (1 s)^2 = h / (3 s)^2

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4 years ago

An imaginary cubical surface of side L has its edges parallel to the x-, y- and z-axes, one corner at the point x = 0, y = 0, z

kodGreya [7K]

Find the given attachment for solution

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3 years ago

A wheel 30 cm in diameter accelerates uniformly from 245 rpm to 380 rpm in 6.1 s . Part A How far will a point on the edge of th

jonny [76]

Answer:

A point on the edge of the wheel will travel 199.563 radians at the given time.

Explanation:

Given;

initial angular velocity of the wheel; $\omega _i = 245 \ rev/\min = 245\ \frac{rev}{\min} \times \frac{2\pi}{1\ rev} \times \frac{1 \ \min}{60 \ s} = 25.66 \ rad/s$

final angular velocity of the wheel;

$\omega _f = 380 \ rev/\min = 380 \ \frac{rev}{\min} \times \frac{2\pi}{1\ rev} \times \frac{1 \ \min}{60 \ s} = 39.80 \ rad/s$

radius of the wheel, d/2 = (30 cm ) / 2 = 15 cm = 0.15 m

time of motion, t = 6.1 s

The angular distance traveled by the edge of the wheel is calculated as;

$\theta = (\frac{\omega_f + \omega_i}{2} )t\\\\\theta = (\frac{39.8 + 25.66}{2} )\times 6.1\\\\\theta = 199.653 \ radian$

Therefore, a point on the edge of the wheel will travel 199.563 radians at the given time.

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3 years ago

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