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Troyanec [42]
3 years ago
13

Solve each system by substitution. 1) y = 2x + 2 y = -5x + 16

Mathematics
2 answers:
dalvyx [7]3 years ago
5 0

Answer:

y = 6

x = 2

Step-by-step explanation:

rearrange the first equation in terms of x

x = (y - 2)/2

substiute x in the second equation

y = -5[(y-2)/2] +16

Now simpilify and solve for y

y = (-5y + 10)/2 +16

y = -5/2y + 5 + 16

y + 5/2y = 5 + 16

3.5y = 21

y = 6

Now substitue y in the first equation to solve for x

x = (6 - 2)/2

x = 2

jekas [21]3 years ago
5 0

Answer:

(2, 6)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = 2x + 2

y = -5x + 16

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                     2x + 2 = -5x + 16
  2. Add 5x on both sides:         7x + 2 = 16
  3. Subtract 2 on both sides:    7x = 14
  4. Divide 7 on both sides:        x = 2

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define equation:                    y = 2x + 2
  2. Substitute in <em>x</em>:                       y = 2(2) + 2
  3. Multiply:                                  y = 4 + 2
  4. Add:                                        y = 6
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