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3 years ago

Solve each system by substitution. 1) y = 2x + 2 y = -5x + 16

Mathematics

2 answers:

dalvyx [7]3 years ago

5 0

Answer:

y = 6

x = 2

Step-by-step explanation:

rearrange the first equation in terms of x

x = (y - 2)/2

substiute x in the second equation

y = -5[(y-2)/2] +16

Now simpilify and solve for y

y = (-5y + 10)/2 +16

y = -5/2y + 5 + 16

y + 5/2y = 5 + 16

3.5y = 21

y = 6

Now substitue y in the first equation to solve for x

x = (6 - 2)/2

x = 2

jekas [21]3 years ago

5 0

Answer:

(2, 6)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Terms/Coefficients
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = 2x + 2

y = -5x + 16

Step 2: Solve for x

Substitution

Substitute in y: 2x + 2 = -5x + 16
Add 5x on both sides: 7x + 2 = 16
Subtract 2 on both sides: 7x = 14
Divide 7 on both sides: x = 2

Step 3: Solve for y

Define equation: y = 2x + 2
Substitute in x: y = 2(2) + 2
Multiply: y = 4 + 2
Add: y = 6

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