a) The capacitance is 12.8 nF
b) The charge stored is 154 nC
c) The maximum voltage supported is 1600 V
Explanation:
a)
The capacitance of a parallel-plate capacitor is given by

where
k is the relative permittivity of the material between the plates
is the vacuum permittivity
A is the area of each plate of the capacitor
d is the separation between the plates
For the capacitor in this problem, we have:
k = 2.3 for paper


Therefore, the capacitance is

b)
The charge stored on a capacitor is related to the potential difference applied by the equation:
Q = CV
where
C is the capacitance
V is the potential difference applied
In this problem, we have

V = 12 V
Substituting,

c)
The dielectric strength for paper is

Which means that this is the maximum electric field that can be supported in the capacitor before charges start to flow from one plate to the other, crossing the gap.
In a parallel plate capacitor, the electric field is uniform, so it is related to the potential difference by

where d is the separation between the plates.
Therefore, by substituting:

and

We find the maximum voltage supported by the capacitor:

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