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PolarNik [594]
3 years ago
8

A "homemade" capacitor can be built by placing a sheet of paper between two foil. Imagine that the sheet of paper is 21 cm x 30

cm and a thickness of 0.10 mm. a) What would be the capacitor capacity? b) What charge does it store if it is connected to a 12V battery? c) What maximum voltage could it support?
Physics
1 answer:
Anit [1.1K]3 years ago
8 0

a) The capacitance is 12.8 nF

b) The charge stored is 154 nC

c) The maximum voltage supported is 1600 V

Explanation:

a)

The capacitance of a parallel-plate capacitor is given by

C=\frac{k \epsilon_0 A}{d}

where

k is the relative permittivity of the material between the plates

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity

A is the area of each plate of the capacitor

d is the separation between the plates

For the capacitor in this problem, we have:

k = 2.3 for paper

d = 0.10 mm = 1\cdot 10^{-4}m

A=(21 cm)(30 cm) = (0.21 m)(0.30 m)=0.063 m^2

Therefore, the capacitance is

C=\frac{(2.3)(8.85\cdot 10^{-12})(0.063)}{1\cdot 10^{-4}}=1.28\cdot 10^{-8} F = 12.8 nF

b)

The charge stored on a capacitor is related to the potential difference applied by the equation:

Q = CV

where

C is the capacitance

V is the potential difference applied

In this problem, we have

C=1.28\cdot 10^{-9}F

V = 12 V

Substituting,

Q=(1.28\cdot 10^{-8})(12)=1.54\cdot 10^{-7} C = 154 nC

c)

The dielectric strength for paper is

E=16 MV/m = 16\cdot 10^6 V/m

Which means that this is the maximum electric field that can be supported in the capacitor before charges start to flow from one plate to the other, crossing the gap.

In a parallel plate capacitor, the electric field is uniform, so it is related to the potential difference by

V=Ed

where d is the separation between the plates.

Therefore, by substituting:

E=16\cdot 10^6 V/m

and

d=1\cdot 10^{-4} m

We find the maximum voltage supported by the capacitor:

V=(16\cdot 10^{6})(1\cdot 10^{-4})=1600 V

Learn more about capacitors:

brainly.com/question/10427437

brainly.com/question/8892837

brainly.com/question/9617400

#LearnwithBrainly

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8 0
2 years ago
Find the acceleration that can result from a net force of 13 N exerted on a 3.6-kg cart. (Note: The unit N/kg is equivalent to m
STatiana [176]

Answer:

a = 3.61[m/s^2]

Explanation:

To find this acceleration we must remember newton's second law which tells us that the total sum of forces is equal to the product of mass by acceleration.

In this case we have:

F = m*a\\\\m=mass = 3.6[kg]\\F = force = 13[N]\\13 = 3.6*a\\a = 3.61[m/s^2]

7 0
3 years ago
At an air show, a stunt pilot performs a vertical loop-the-loop in a circle of radius 3.63 x 103 m. During this performance the
san4es73 [151]

Answer:

189 m/s

Explanation:

The pilot will experience weightlessness when the centrifugal force, F equals his weight, W.

So, F = W

mv²/r = mg

v² = gr

v = √gr where  v = velocity, g = acceleration due to gravity = 9.8 m/s² and r = radius of loop = 3.63 × 10³ m

So, v = √gr

v = √(9.8 m/s² × 3.63 × 10³ m)

v = √(35.574 × 10³ m²/s²)

v = √(3.5574 × 10⁴ m²/s²)

v = 1.89 × 10² m/s

v = 189 m/s

5 0
3 years ago
A camera takes a properly exposed photo with a 4.0 mm diameter aperture and a shutter speed of 1/1000 s. If the photographer foc
hoa [83]

Answer:

option E

Explanation:

given,

diameter = 4 mm

shutter speed = 1/1000 s

diameter of aperture = ?

shutter speed = 1/250 s

exposure time to the shutter time

E V = log_2(\dfrac{N^2}{t})

N is the diameter of the aperture and t is the time of exposure

now,

log_2(\dfrac{N^2}{t_1})=log_2(\dfrac{N^2}{t_2})

\dfrac{N_1^2}{t_1}=\dfrac{N_2^2}{t_2}

inserting all the values

\dfrac{4^2}{1000}=\dfrac{N_2^2}{250}

      N₂² = 4

      N₂ = 2 mm

hence , the correct answer is option E

4 0
3 years ago
A mother and daughter press their hands together and then push apart while ice skating. Immediately after they push away from ea
kherson [118]

Answer:

J

Explanation:

The daughter moves with greater acceleration backwards because of her weight.

7 0
2 years ago
Read 2 more answers
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