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Zanzabum
3 years ago
11

The space shuttle travels at about 28,000 km per hour. Using that information, estimate how many hours it will take the shuttle

to reach Saturn from Earth. Show your work. Convert your answer into scientific notation if necessary.
Physics
1 answer:
jasenka [17]3 years ago
3 0
It depends what is the position of earth and saturn. Distance from earth to saturn varies depending on whether earth is between sun and saturn or sun is between earth and saturn. Obviously, the shortest distance will be if earth is between sun and saturn. we will take that the distance between earth and saturn is:

s = 1 275 000 000 km
The time required to travel that distance is:
t = s/v = 45535 hours or 1897.3 days
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3 years ago
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Can you ever absolutely prove that a hypothesis is correct? Explain.
Diano4ka-milaya [45]

Yes you can, with using scientific experiment.

Ask a question -- Do background Research -- Construct a Hypothesis --Test with an Experiment -- Procedure working? -- Yes or no? -- Analyze Data and Draw Conclusions

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8 0
3 years ago
Calculate the momentum of a Lion of mass 130-kg and moving at a speed of 22.3 m/s [W]
Sunny_sXe [5.5K]

Answer:

<h2>289.9 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 130 × 22.3

We have the final answer as

<h3>289.9 kg.m/s</h3>

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3 years ago
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5 0
3 years ago
A uniform thin wire is bent into a quarter-circle of radius a = 20.0 cm, and placed in the first quadrant. Determine the coordin
Mashcka [7]

Answer:

r_{cm}=[12.73,12.73]cm

Explanation:

The general equation to calculate the center of mass is:

r_{cm}=1/M*\int\limits {r} \, dm

Any differential of mass can be calculated as:

dm = \lambda*a*d\theta  Where "a" is the radius of the circle and λ is the linear density of the wire.

The linear density is given by:

\lambda=M/L=M/(a*\pi/2)=\frac{2M}{a\pi}

So, the differential of mass is:

dm = \frac{2M}{a\pi}*a*d\theta

dm = \frac{2M}{\pi}*d\theta

Now we proceed to calculate X and Y coordinates of the center of mass separately:

X_{cm}=1/M*\int\limits^{\pi/2}_0 {a*cos\theta*2M/\pi} \, d\theta

Y_{cm}=1/M*\int\limits^{\pi/2}_0 {a*sin\theta*2M/\pi} \, d\theta

Solving both integrals, we get:

X_{cm}=2*a/\pi=12.73cm

Y_{cm}=2*a/\pi=12.73cm

Therefore, the position of the center of mass is:

r_{cm}=[12.73,12.73]cm

5 0
3 years ago
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