<h2>
Answer:</h2>
(a) 10N
<h2>
Explanation:</h2>
The sketch of the two cases has been attached to this response.
<em>Case 1: The box is pushed by a horizontal force F making it to move with constant velocity.</em>
In this case, a frictional force 
is opposing the movement of the box. As shown in the diagram, it can be deduced from Newton's law of motion that;
∑F = ma -------------------(i)
Where;
∑F = effective force acting on the object (box)
m = mass of the object
a = acceleration of the object
∑F = F -
m = 50kg
a = 0 [At constant velocity, acceleration is zero]
<em>Substitute these values into equation (i) as follows;</em>
F - = m x a
F - = 50 x 0
F - = 0
F = -------------------(ii)
<em>Case 2: The box is pushed by a horizontal force 1.5F making it to move with a constant velocity of 0.1m/s²</em>
In this case, the same frictional force is opposing the movement of the box.
∑F = 1.5F -
m = 50kg
a = 0.1m/s²
<em>Substitute these values into equation (i) as follows;</em>
1.5F - = m x a
1.5F - = 50 x 0.1
1.5F - = 5 ---------------------(iii)
<em>Substitute </em><em> = F from equation (ii) into equation (iii) as follows;</em>
1.5F - F = 5
0.5F = 5
F = 5 / 0.5
F = 10N
Therefore, the value of F is 10N
<em />
Answer:
I think it is the last one.
Explanation:
I am not sure because i am stuck on this one, too.
<em>why Is there just a random "u" in the middle of the equation </em><em>awa</em><em> </em>
<em> </em><em>t</em><em>h</em><em>e</em><em>question is impossible to do btw </em>
<em>Imao the u in the middle doesn't makes sense </em>
if<em> you edit the question I'll help you w it)</em>
have a good day bro cya
The wavelength for C1 note is 10.40 m, for A6 note is 0.193 m and for B7 note 0.086 m.
Answer:
Explanation:
Since, wavelength, frequency and speed of sound waves are related to each other, we can determine a single parameter with the help of other two parameters. So in this case, the frequency of different notes are given along with their common speed. So as the frequency is inversely proportional to the wavelength then in this case, the wavelength of the notes will be maximum for C1 and minimum for 3951.1 Hz.
Wavelength = Speed / Frequency
Wavelength for C1 note = 340 / 32.7 =10.40 m
Similarly, the wavelength for A6 note = 340/1760=0.193 m
And, the wavelength for B7 note = 340/3951.1 = 0.086 m
So, the wavelength for C1 note is 10.40 m, for A6 note is 0.193 m and for B7 note 0.086 m.
