Ask question

Ask question

All categories

3 years ago

14

Which 2 skill related components of fitness are the most important skills needed to be successful in juggling?

1 answer:

Schach [20]3 years ago

6 0

Answer:

1. eye hand and/or foot coordination

2. strength and speed

Explanation:

You might be interested in

Bile_____. <br> I WILL GIVE 30 POINTS AND BRAINLEST ANSWER

seropon [69]

Answer:

Bile is a fluid that is made and released by the liver and stored in the gallbladder.

Explanation:

So basically it helps with helps with digestion.

5 0

3 years ago

Which statement accurately describes a difference between mitosis and meiosis I need this done now like super fast so whoever ca

stealth61 [152]

Mitosis involves the division of body cells, while meiosis involves the division of sex cells. — Two daughter cells are produced after mitosis and cytoplasmic division, while four daughter cells are produced after meiosis. Daughter cells resulting from mitosis are diploid, while those resulting from meiosis are haploid.

8 0

3 years ago

Which of the following is not a symptom of anorexia nervosa?

boyakko [2]

I'm guessing b but I'm not sure

5 0

3 years ago

Read 2 more answers

8. The old lady put the dishes in the sink. Change this sentence to passive voice. *

BaLLatris [955]

Answer:

The dishes were put in the sink by the old lady.

Explanation:

When using passive voice the subject is acted upon by the verb.

4 0

3 years ago

If 2^x=3^y=12^z, show that 1÷z=1÷y+2÷x.....

Ostrovityanka [42]

Answer:

Proof of $\dfrac{1}{z}}=\dfrac{1}{y}+\dfrac{2}{x}$ is shown below.

Explanation:

The given equation is

$2^x=3^y=12^z$

To prove : $\dfrac{1}{z}=\dfrac{1}{y}+\dfrac{2}{x}$

Proof : Let as assume,

$2^x=3^y=12^z=k$

$2^x=k\Rightarrow 2=k^{\frac{1}{x}}$ ...(1)

$3^y=k\Rightarrow 3=k^{\frac{1}{y}}$ ...(2)

$12^z=k\Rightarrow 12=k^{\frac{1}{z}}$ ...(3)

We know that

$12=2\times 2\times 3$

$12=(2)^2\times 3$

Using (1), (2) and (3), we get

$k^{\frac{1}{z}}=(k^{\frac{1}{x}})^2\times k^{\frac{1}{y}}$

$k^{\frac{1}{z}}=k^{\frac{2}{x}}\times k^{\frac{1}{y}}$

$k^{\frac{1}{z}}=k^{\frac{2}{x}+\frac{1}{y}}$

On comparing both sides, we get

$\dfrac{1}{z}}=\dfrac{2}{x}+\dfrac{1}{y}$

$\dfrac{1}{z}}=\dfrac{1}{y}+\dfrac{2}{x}$

Hence proved.

8 0

3 years ago