Centriole
vacuole
lysosome
cell membrane
liver
and so many more
Answer:- Third choice is correct, 17.6 moles
Solution:- The given balanced equation is:
We are asked to calculate the moles of potassium hydroxide needed to completely react with 2.94 moles of aluminium sulfate.
From the balanced equation, there is 1:6 mol ratio between aluminium sulfate and potassium hydroxide.
It is a simple mole to mole conversion problem. We solve it using dimensional set up as:
= 17.6 mol KOH
So, Third choice is correct, 17.6 moles of potassium hydroxide are required to react with 2.94 moles of aluminium sulfate.
Answer:
Relative molecular of the compound or infomation like vapour density, volume occupied by a known mass of its vapour at stp, etc
Explanation:
The molecular mass of a compound is twice its vapour density. We can find the molecular formula using the relationship below:
- Empirical formula is the simplest formula of a compound. It repeats itself "n" times to become a molecular formula i.e (EF)ₙ = MF...... n is the number of times the empirical formula presents in a mole of the compound.
- Most times, n is a whole number like 1,2,3,.....
Answer:
V₂ = 21.3 dm³
Explanation:
Given data:
Initial volume of gas = 3.00 dm³
Initial pressure = 101 Kpa
Final pressure = 14.2 Kpa
Final volume = ?
Solution;
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
101 Kpa × 3.00 dm³ = 14.2 Kpa × V₂
V₂ = 303 Kpa. dm³/ 14.2 Kpa
V₂ = 21.3 dm³
Explanation:
