All categories

3 years ago

Is fire a source of chemical energy

Chemistry

1 answer:

Leno4ka [110]3 years ago

4 0

Answer:

Any matter considered to be a fuel contains chemical energy

Energy has to be provided to initiate the reaction.

So yes. It is

You might be interested in

True or False : Not all metals are ferromagnetic-only the ones with iron,<br> nickel, or cobalt. *

Triss [41]

Answer: True
Hope this helps!

5 0

2 years ago

Read 2 more answers

Which of the following chemical equations represents an oxidation-reduction reaction?

zimovet [89]

C. Represents an oxidation-reduction reaction

7 0

3 years ago

If an element has a half life of one million years, how long will it take to be completely gone

Aleonysh [2.5K]

It should be 2 million years

3 0

3 years ago

4.8 L sample of helium gas contains 0.22 moles of helium - How many additional moles of herum gas must be added to the sample to

yawa3891 [41]

Answer:

Explanation:

7 0

2 years ago

A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235

trapecia [35]

Answer : The value of $\Delta E$ of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

$\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}$

Molar mass of helium = 4 g/mole

$\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole$

Now we have to calculate the heat.

Formula used :

$q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)$

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

$c_p$ = specific heat of helium = 20.8 J/mol.K

$T_1$ = initial temperature = 310.0 K

$T_2$ = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

$q=nc_p(T_2-T_1)$

$q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K$

$q=-19.5J$

Now we have top calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 1.21 L

$V_2$ = final volume = 0.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (0.99-1.21)L$

$w=0.22L.artm=0.22\times 101.3J=22.29J$

conversion used : (1 L.atm = 101.3 J)

Now we have to calculate the value of $\Delta E$ of the gas.

$\Delta E=q+w$

$\Delta E=(-19.5J)+22.29J$

$\Delta E=2.79J$

Therefore, the value of $\Delta E$ of the gas is 2.79 Joules.

3 0

3 years ago

Is fire a source of chemical energy￼

Is fire a source of chemical energy