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Makovka662 [10]
3 years ago
11

Rocco has a weekly reading schedule, reading for 4.5 hours per day on some days and 3.5 hours per day on the other days. He read

s a total of 25.5 hours in a seven-day week. On how many days does he read for 4.5 hours?
Mathematics
1 answer:
AleksAgata [21]3 years ago
4 0

Answer:

x = days he reads for 4.5 hours = 1 day

y = days he reads for 3.5 hours = 6 days

Step-by-step explanation:

Let

x = days he reads for 4.5 hours

y = days he reads for 3.5 hours

x + y = 7 (1)

4.5x + 3.5y = 25.5 (2)

From (1)

x = 7 - y

Substitute x = 7 - y into (2)

4.5x + 3.5y = 25.5 (2)

4.5(7 - y) + 3.5y = 25.5

31.5 - 4.5y + 3.5y = 25.5

- 4.5y + 3.5y = 25.5 - 31.5

-y = -6

y = 6

Substitute y = 6 into (1)

x + y = 7 (1)

x + 6 = 7

x = 7 - 6

x = 1

x = days he reads for 4.5 hours = 1 day

y = days he reads for 3.5 hours = 6 days

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<u>Needed information</u>

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

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We are told that the probability that the counter is <em>not </em>white is 2/3.  

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We are told that there are black, white and grey counters in the bag.  We also know that the sum of the probabilities of all outcomes must equal 1.  Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}

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2 years ago
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