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nalin [4]
3 years ago
10

Show that 4x - x? – 7 is always negative. Help

Mathematics
1 answer:
Verizon [17]3 years ago
6 0

                                          <em>Question No 7</em>

Answer:

Please check the explanation.

Step-by-step explanation:

Show that 4x - x² - 7 is always negative.

Given

4x - x² - 7

4x - x² - 7 is always negative because:

  • -x²-7 will alwas be negative for all the values of x,
  • The value of  - x² - 7 will always be less than 4x for all the values of x

Hence, 4x - x² - 7 is always negative

For example,

let suppose we enter x = 1

4(1)-1^{2} -7\\=4-1-7\\=4-8\\=-4

let suppose we enter x = -1

4(-1)-(-1)^{2} - 7\\= -4 - 1 - 7\\= -12

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3 years ago
Whats the difference between 8.3 and 8.03
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Domain and range of the inequality y&lt;√x+3 +1
Margaret [11]

The domain of the given inequality is y>1.

<h3>What is Inequality?</h3>

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

Here, given inequality:

              y < \sqrt{x+3}+1

Related equation:

             y = \sqrt{x+3}+1

The equation defined as,

    x+3 > 0

    x > -3

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

    \sqrt{x+3} \geq 0

adding 1 on both sides, we get

  \sqrt{x+3} + 1 \geq  1

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The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

Thus, the domain of the given inequality is y>1.

Learn more about Inequality from:

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2 years ago
The equation of the line that goes through the point (−10,8) and (−3,-4) can be written in the form y=mx+b
Y_Kistochka [10]

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