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Alchen [17]
2 years ago
12

If J M = 9 and K M = 4 , what is the approximate perimeter of Δ J K L ? 26.2 26.2 29.8 29.8 31.0 31.0 31.7

Mathematics
1 answer:
Nataly [62]2 years ago
7 0

Answer:

Correct option is (a)

Step-by-step explanation:

According to question in the triangle ΔJKL

JK = 9 and KL =4

according to the condition of triangle sum of two sides must be greater than the third side

Here sum of its two sides is 9 + 4 = 13

⇒ third side must be greater than 13 say 13.2 = JL

therefore, perimeter of triangle ΔJKL is

JK + KL + JL = 9 + 4 + 13.2 = 26.2

Therefore correct option is (a)

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GuDViN [60]

Answer:

Option D. 13122 is the answer.

Step-by-step explanation:

As we can see from the table having interval and average rate of change, figures under average rate of change are forming a geometric sequence.

Sequence is 2, 6, 18 , 54, 162, 486.

and we have to find the average rate of change from x = 8 to x = 9, means we have to find 9th term of the given sequence.

Now we know that explicit formula of the sequence can be written as T_{n}=ar^{n-1}

where Tn is the nth term of the sequence.

a = first term

r = common ratio

n = number of the term

Now from this explicit formula we can find the 9th term of the sequence.

From the given table

a = 2, r = 3, n = 9

T_{9}=2.3^{9-1}=2.3^{8}

T9 = 13122

Therefore Option D. 13122 will be the answer.

6 0
3 years ago
How you could multiple 6×99 in your head?
Andrew [12]
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4 0
3 years ago
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Answer:

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4 0
2 years ago
a) The quadratic 3x^2-12x-11 can be written in the form 3(x+a)^2+b. Find the values of a and b. b) Given that the solutions of t
LenKa [72]

Answer:

Step-by-step explanation:

a) 3x^2-12x-11=3*x^2-3*2*2*x+3*4-23=3*(x^2-2*2x+2^2)-23=3*(x-2)^2-23

so  a= -2 ,b= -23

b) x1=[12+V(12^2-4*3* -11)]/6=12/6+V(144+132)/6=2+2/6V69=2+1/3V69=

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5 0
2 years ago
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Studentka2010 [4]

9514 1404 393

Answer:

  A.  7 seconds

Step-by-step explanation:

We assume your factored equation is something like ...

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