PLEASE HELP WILL MARK BRAINLIEST

Mathematics

1 answer:

Tpy6a [65]2 years ago

4 0

Answer:

$slop = \frac{2 - 1}{2 - 0} = \frac{1}{2} \\ for \: point \: x = 0 \: y = 1 \\ y - 1 = \frac{1}{2} \times (x - 0) \\ y = \frac{1}{2} x + 1$

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Hello If You Have Please Help Thank You Solve for x. −7x−15<6

bonufazy [111]

Answer:

x > -22/7

Step-by-step explanation:

Given inequality:

- 7x - 15 < 6

adding 15 to both sides:

==> -7x - 15 + 15 < 6 + 16

==> -7x < 22

dividing both sides by 7:

==> -x < 22/ 7

multiplying both sides by -1

(anytime you multiply the inequality by -1 you must flip the inequality sign– replace the "<" with ">")

==> x > -22/7

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1 year ago

What is 13/78 redused to its lowest form

Wewaii [24]

Divide to get a low form of a fraction.
13 divide by 13 = 1
78/13 = 6

1/6 would therefore, be the lowest form

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3 years ago

Read 2 more answers

two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe

sveta [45]

Applying the required rule or theorem, it can be concluded that the second biker is farther from the parking lot. The distance of the bikers to the parking lot are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The path of travel of both bikers would form a triangle. Applying the Pythagoras theorem to the path of the first biker would give his distance from the starting point. While applying the cosine rule to the path of second rider would gives his distance to the starting point.

Thus,

a. To determine the distance of the first biker from the parking lot.

Let the required distance be represented by x. Applying the Pythagoras theorem, we have:

$hyp^{2}$ = $adj 1^{2}$ + $adj 2^{2}$