Hi!
The correct options would be:
1. Cathode - <em>reduction</em>
The cathode is the negatively charged electrode, and so has an excess of electrons. Cations (positively charged ions) are attracted to the cathode, and gain electrons to acquire a neutral charge. The process in which a gain of electron occurs is called reduction.
2. Anode - <em>oxidation</em>
The opposite occurs at the anode which is positively charged and attracts negatively charged ions, anions. These anions lose their electrons at the anode to acquire a neutral charge, and the process involving loss of electrons is known as oxidation.
3. Salt Bridge - <em>ion transport </em>
Salt bridge is a physical connection between the the anodic and cathodic half cells in an electrochemical cell and is a pathway that facilitates the flow of ions back and forth these half cells. Salt bridge is involved in maintaining a neutral condition in the electrochemical cells, and its absence would result in the accumulation of positive charge in the anodic cell, and negative charge in the cathodic cell.
4. Wire - <em>electron transport </em>
Wires have a universal role of being a pathway for the transport of electrons in circuit. This role is also the same in the wires involved in an electrochemical cells where they are used to transport electrons from the anodic half cell, and this electron transport results in the generation of electricity in the internal circuit of the electrochemical cell.
Hope this helps!
0.8 moles
3 moles of feO gives you 2 moles of Al and 1.2 of your moles should give you 1.2 divided by 3*2 so it equals 0.80 moles
Right?
So what I know is that enzyme and substrate are like lock and key meaning that when the active site of the enzyme changes, the enzyme will not fit to the substrate which will lead the enzyme to denature. Hope this helps.
Answer:
1. q.
2. 2q.
3. 3q.
4. 6q.
Explanation:
We'll begin by calculating the specific heat capacity of the liquid. This can be obtained as follow:
Mass (m) = 25 g
Change in temperature (ΔT) = 20 °C
Heat (Q) = q
Specific heat capacity (C) =?
Q = MCΔT
q = 25 × C × 20
q = 500C
Divide both side by 500
C = q/500
C = 2×10¯³ qg°C
Therefore, the specific heat capacity of liquid is 2×10¯³ qg°C
Now, we shall determine the heat required to produce the various change in temperature as follow:
2. Mass (m) = 50 g
Change in temperature (ΔT) = 20 °C
Specific heat capacity (C) = 2×10¯³ qg°C
Heat (Q) =?
Q = MCΔT
Q = 50 × 2×10¯³ × 20
Q = 2q.
Therefore, the heat required is 2q.
3. Mass (m) = 25 g
Change in temperature (ΔT) = 60 °C
Specific heat capacity (C) = 2×10¯³ qg°C
Heat (Q) =?
Q = MCΔT
Q = 25 × 2×10¯³ × 60
Q = 3q.
Therefore, the heat required is 3q.
4. Mass (m) = 50 g
Change in temperature (ΔT) = 60 °C
Specific heat capacity (C) = 2×10¯³ qg°C
Heat (Q) =?
Q = MCΔT
Q = 50 × 2×10¯³ × 60
Q = 6q.
Therefore, the heat required is 6q.
