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3 years ago

You leave gasoline in an open can and it vaporizes. What type of change is this?

Chemistry

2 answers:

DerKrebs [107]3 years ago

6 0

Answer:

evaporation

Explanation:

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UNO [17]3 years ago

3 0

Answer:evaporation

Explanation:

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Why is it important to use chemicals of high quality (purity) and exact(correct) concentrations in experiments?

Darya [45]

It is important to use chemicals of high quality and correct concentrations in experiment so that we can obtain the predictable result in an experiment

Purity of substances/chemicals is very important when performing experiments in the laboratories, because it plays an important role in the determination of the chemical properties of substances which will have a direct effect on the result obtained from the experiment. likewise using the correct concentration of reagents

During experiments to obtain the best/predictable result in an experiment it is of best practice to make use of chemicals of high quality and also at the exact(needed) concentrations, that way the predictable result of the experiment will be obtained.

Learn more : brainly.com/question/8684258

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2 years ago

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Government should use informed science to help make policies protect all citizens True or False

Sloan [31]

Answer:

yes

Explanation:

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2 years ago

What is wrong with this model of the atom.

sp2606 [1]

Answer:

A. The neutrons and electrons are in the wrong place.

Explanation:

The atom's nucleus contains both protons and neutrons, whilst the electrons are arranged in shells around the nucleus.

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2 years ago

1. How is the law of conservation of mass shown by a balanced chemical equation?

Ilia_Sergeevich [38]

Answer:

Explanation:

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2 years ago

A breeder nuclear reactor is a reactor in which nonfissile U-238 is converted into fissile Pu-239. The process involves bombardm

VARVARA [1.3K]

Answer: The nuclear equations for the given process is written below.

Explanation:

The chemical equation for the bombardment of neutron to U-238 isotope follows:

$_{92}^{238}\textrm{U}+n\rightarrow _{92}^{239}\textrm{U}$

Beta decay is defined as the process in which neutrons get converted into an electron and a proton. The released electron is known as the beta particle.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

The chemical equation for the first beta decay process of $_{92}^{239}\textrm{U}$ follows:

$_{92}^{239}\textrm{U}\rightarrow _{93}^{239}\textrm{Np}+_{-1}^0\beta$

The chemical equation for the second beta decay process of $_{93}^{239}\textrm{Np}$ follows:

$_{93}^{239}\textrm{Np}\rightarrow _{94}^{239}\textrm{Pu}+_{-1}^0\beta$

Hence, the nuclear equations for the given process is written above.

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2 years ago